The following are the expressions, sage: var('x1,t1,x2,t2,u,c',domain=RR);assume(u>0);assume(c>u); (x1, t1, x2, t2, u, c) sage: T1 = (t1-((u*x1)/(c^2)))/sqrt(1-((u^2)/(c^2))) sage: T2 = (t2-((u*x2)/(c^2)))/sqrt(1-((u^2)/(c^2))) sage: dT = T2-T1 sage: dt = t2-t1
Suppose I know that dT is in this form, dT = a*dt + b, Assuming I DID NOT know that, a = 1/sqrt(1-((u^2)/(c^2))) , b = (u*(x2 - x1))/((c^2)*sqrt(1-((u^2)/(c^2)))) , is there any way I can find 'a' and 'b' using Sage? What if I didn't know that dT is in the form of a*dt + b, but just knew dT in terms of x1,t1,x2,t2,u and c ? Can I still express dT in terms of dt using sage? -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org