Hi, I’m puzzled about the following behavior. Two integer matrices only differ by a linear transformation, but their BKZ output is different.
transfer=matrix(2,2,[[1,0],[27/20,-1/20]]) print transfer [ 1 0] [27/20 -1/20] AA=matrix(ZZ,2,5,[[3,1,-1,-3,0],[81,-73,-127,99,20]]) print AA [ 3 1 -1 -3 0] [ 81 -73 -127 99 20] BB=matrix(ZZ,2,5,[[3,1,-1,-3,0],[0,5,5,-9,-1]]) print BB [ 3 1 -1 -3 0] [ 0 5 5 -9 -1] print transfer*AA [ 3 1 -1 -3 0] [ 0 5 5 -9 -1] Why are AA.BKZ() and BB.BKZ() different? print AA.BKZ() [ 3 1 -1 -3 0] [ 81 -73 -127 99 20] print BB.BKZ() [ 3 1 -1 -3 0] [-3 4 6 -6 -1] Is there a method which converts AA into BB.BKZ()? Thanks for your reply! Roland -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
