I had it turned on but I guess it doesn't get triggered for x (x -1). Any way to change the behavior or does that require a patch to Sage?
On Dec 15, 1:37 am, Jason Grout <jason-s...@creativetrax.com> wrote: > On 12/15/11 1:31 AM, Chris Seberino wrote: > > > I know Sage has some issues with a variable in front of parens when > > using implicit multiplication. Why did that make the first give the > > wrong answer when using implicit multiplication? How is sage > > interpreting it? > > > sage: solve(3 + x (x-1)==5,x) > > [x == 3] > > sage: solve(3 + x*(x-1)==5,x) > > [x == 2, x == -1] > > You have to explicitly turn on implicit multiplication; it's not on by > default. In your case above, it's not on (unless you turned it on) > > So "x(x-1)" is interpreted as: > > f(x)=x > f(x-1) > > i.e., x(x-1) is just x-1 (the function y=x evaluated at x-1) > > Thanks, > > Jason -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
