Justin, I don't think that is the issue here: you are referring to the debate between using a,2*b,c as coefficeints rather than a,b,c. But here *all* the coefficients have been doubled.
Note that we also have sage: BinaryQF([1,2,3]) x^2 + 2*x*y + 3*y^2 john On 24 February 2012 16:04, Jacob Hicks <jhi...@math.uga.edu> wrote: > When I run: > > sage: q = QuadraticForm(ZZ,2,[3,2,5]) > sage: q.polynomial() > 6*x0^2 + 4*x0*x1 + 10*x1^2 > > I would expect to get half of this result, which is the quadratic form > as a polynomial. The doc tests say this is what the behavior should > be, but I don't understand why. Is this actually the desired behavior > and if so what am I misunderstanding? > > Thanks, > -- > Jacob Hicks > > -- > To post to this group, send email to sage-support@googlegroups.com > To unsubscribe from this group, send email to > sage-support+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/sage-support > URL: http://www.sagemath.org -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
