thanks wasn't even thinking about a dictionary.
On Monday, May 21, 2012 10:05:26 AM UTC-7, John H Palmieri wrote:
>
>
>
> On Monday, May 21, 2012 9:49:08 AM UTC-7, Eric Kangas wrote:
>>
>> When dealing with base 36 I realized there is no letter available to use
>> in for loops.
>>
>> Here is the code that I have right now.
>>
>> a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z =
>> var('a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z')
>>
>> pie = pi.n(1000)
>>
>> pie36 = list(pie.str(base=36))
>>
>> pie36.remove('.')
>>
>> a = 10; b = 11; c = 12; d = 13; e = 14; f = 15; g = 16; h = 17; i = 18; j
>> = 19; k = 20; l = 21; m = 22; n = 23; o = 24; p = 25; q = 26; r = 27; s =
>> 28; t = 29; u = 30; v = 31; w = 32; x = 33; y = 34; z = 35;
>>
>> pie36 = [int(ii) for ii in pie36]
>>
>>
>> I tried using ii for the increment count for the for loop, but here is
>> what I get as the error.
>>
>>
>> ---------------------------------------------------------------------------
>> ValueError Traceback (most recent call last)
>>
>> /home/nooniensoong97/<ipython console> in <module>()
>>
>> ValueError: invalid literal for int() with base 10: 'i'
>>
>>
>>
>>
>> I guess you can not use more then a letter to count the increments in the
>> loop? Is there anyway to get around this issue?
>>
>
> How about:
>
> sage: D = dict([(Integer(j).str(base=36),j) for j in range(36)])
>
> (This creates a dictionary with entries like '3':3 and 'a':10, associating
> a base 36 representation as a string to the corresponding integer.) Then
>
> sage: pie = pi.n(1000)
>
> sage: pie36 = list(pie.str(base=36))
>
> sage: pie36.remove('.')
> sage: [D[ii] for ii in pie36]
>
> ought to do what you want.
>
> --
> John
>
>
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