On 5 September 2012 02:41, Cindy <cindy425192...@gmail.com> wrote:
> Hi, David,
>
> Yes, that's what I mean. Can I find it using sage?
>
> Thanks.
>
> Cindy

sage: K.<z> = NumberField(x^3 - x + 17)
sage: I = K.primes_above(17)[0]
sage: K.trace_dual_basis(I.basis())
[4/132583*z^2 + 6/7799*z + 2597/132583, -153/7799*z^2 - 2/7799*z +
102/7799, -6/7799*z^2 - 153/7799*z + 4/7799]

hth, David

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