Thank you very much.
On 26 February 2013 18:52, Christophe BAL <projet...@gmail.com> wrote:
> Hello,
> this is more a python question that a sympy question
>
> If L is the list [{x0:1, x1: 0, y0: 1}], then L[0] is the dictionnary
> {x0:1, x1: 0, y0: 1}. Than you can try something like L[0]["x0"] or
> L[0][x0].
>
> Hoping that this will help you.
>
> Best regards.
> Christophe.
>
>
> 2013/2/26 Santanu Sarkar <sarkar.santanu....@gmail.com>
>
>> Sorry, I can not understand the approach.
>>
>> Let I=[{x0:1, x1: 0, y0: 1}]. Suppose I want to find only x0 and x1.
>> How is it possible?
>>
>>
>> On 26 February 2013 16:37, akhil <lalwani.ak...@gmail.com> wrote:
>>
>>>
>>>
>>> On Tuesday, February 26, 2013 1:40:26 PM UTC+5:30, Santanu wrote:
>>>>
>>>> Dear all,
>>>> I have a set non linear equations over Boolean variables x_1,...,
>>>> x_{10000}.
>>>> Sat solver gives I=[{x1: 0, x100: 1, .....}]. I am interested to see
>>>> only the values
>>>> of x1,.., x100. Will you kindly help me ?
>>>>
>>>
>>>
>>> Hello,
>>>
>>> Let d be the concerned dictionary, whose keys are x1 to x10000, and
>>> corresponding to each key, value is in {0,1}.
>>>
>>> One can do the following:
>>>
>>> l = [ ]
>>> for i in range(1,101):
>>> l.append('x' + str(i))
>>>
>>> d1 = { }
>>>
>>> d1 = {keys:d[keys] for keys in l}
>>>
>>> The result will be the dictionary d1 containing only (key,value) pairs
>>> corresponding to keys x1,....x100.
>>>
>>> Regards,
>>>
>>> AKHIL.
>>>
>>>>
>>>>
>>>>
>>>>
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