This works for me in Sage 5.13 (I don't have an older version installed), 
after replacing the definition of FFps by

FFps.<X>=PolynomialRing(Fps)  # the .<X> was missing

However, without the .<X> the error I got was different from yours 
(TypeError: You must specify the names of the variables.)


Op donderdag 17 april 2014 17:05:20 UTC+1 schreef Irene:
>
> p=3700001
> Fp=GF(p)
> E=EllipticCurve([Fp(3),Fp(5)])
> j=E.j_invariant()
> l=13#Atkin prime
> n=((l-1)/2).round()
> r=2# Phi_13 factorize in factors of degree 2
> s=12#Psi_13 factorize in factors of degree 12
>
> #repsq(a,n) computes a^n
> def repsq(a,n):
>     B = Integer(n).binary()
>     C=list(B)
>     k=len(B)-1
>     bk=a
>     i=1
>     while i <= k:
>         if C[i]=="1":
>             bk=(bk^2)*a
>         else:
>             bk=bk^2
>         i=i+1
>     return bk
>
> d=E.division_polynomial(13)
> Fps=GF(repsq(p,s),'a')
> a=Fps.gen()
> Fpr=GF(repsq(p,r),'b')
> b=Fpr.gen()
> FFps=PolynomialRing(Fps)
> Fl=GF(l)
> c=GF(2)
> rts=d.roots(Fps,multiplicities=False)
> Px=rts[0]
> Py2=Px^3+3*Px+5
> c=Fl.multiplicative_generator()
>
> def produx(n,Qx):
>     if is_odd(n):
>         
> pro=Qx-(E.division_polynomial(n-1,(Qx,1),two_torsion_multiplicity=1)*E.division_polynomial(n+1,(Qx,1),two_torsion_multiplicity=1)*
>  
> (Qx^3+3*Qx+5))/((E.division_polynomial(n,(Qx,1),two_torsion_multiplicity=1)^2))
>     else:
>         
> pro=Qx-(E.division_polynomial(n-1,(Qx,1),two_torsion_multiplicity=1)*E.division_polynomial(n+1,(Qx,1),two_torsion_multiplicity=1))/((Qx^3+3*Qx+5)*E.division_polynomial(n,(Qx,1),two_torsion_multiplicity=1)^2)
>     return pro
>
>
> Ep=(X-produx(2,Px))*(X-produx(4,Px))*(X-produx(8,Px))*(X-produx(3,Px))*(X-produx(6,Px))*(X-produx(12,Px))
>
> bb=b.minpoly().roots(Fps)[0][0]
> i=Fpr.hom([bb],Fps)
> j=i.section()
> PolynomialRing(Fpr,'x')([j(c) for c in Ep.coeffs()]) 
>
> That was the code, and the version is 5.11. Maybe the problem is because 
> the version is too old, but I was using another version and I got many 
> problems and right now I don't have another option.
>
> On Thursday, April 17, 2014 5:47:32 PM UTC+2, John Cremona wrote:
>>
>> On 17 April 2014 08:43, Irene <irene....@gmail.com> wrote: 
>> > I think that this is exactly what I need. Nevertheless I cannot use 
>> neither 
>> > i.section() nor i.inverse_image(). The second one because of the same 
>> reason 
>> > as you, and the first one when I try it is says "TypeError: 'NoneType' 
>> > object is not callable". 
>>
>> You'll have to post your actual code (and say which Sage version) for 
>> us to help debug that! 
>>
>> John 
>>
>> > 
>> > 
>> > On Thursday, April 17, 2014 12:07:18 PM UTC+2, John Cremona wrote: 
>> >> 
>> >> OK, that makes sense now.  It boils down to this: given an element of 
>> >> F12=GF(p^12) which happens to lie in F2 = GF(p^2), how to express it 
>> >> in terms of a generator of F2.  This is not quite as easy as it should 
>> >> be but this works (assuming that you have defined F12 with generator a 
>> >> and F2 with generator b): 
>> >> 
>> >> sage: bb = b.minpoly().roots(F12)[0][0] 
>> >> sage: i = F2.hom([bb],F12) 
>> >> sage: j = i.section() 
>> >> 
>> >> Here we have defined an embedding i of F2 into F12 by find a place to 
>> >> map b (called bb) and set j to be an inverse to i.  (I think we should 
>> >> be use i.inverse_image() but that gave me a NotImplementedError, which 
>> >> is a pity since I have used sort of construction easily in extensions 
>> >> of number fields). 
>> >> 
>> >> Now if f is your polynomial in F12[x] whose coefficients lie in F2 you 
>> can 
>> >> say 
>> >> 
>> >> sage: PolynomialRing(F2,'X')([j(c) for c in f.coeffs()]) 
>> >> 
>> >> to get what you want, I hope! 
>> >> 
>> >> John 
>> >> 
>> >> On 17 April 2014 02:52, Irene <irene....@gmail.com> wrote: 
>> >> > Sorry, I didn't write it correctly. I meant GF(p^12,'a') instead of 
>> >> > GF(p^13,'a'). As 2 divides 12, GF(p^12,'a') is an extension of 
>> >> > GF(p^2,'b'). 
>> >> > My question is the same now with the correct data. 
>> >> > 
>> >> > On Thursday, April 17, 2014 11:04:40 AM UTC+2, John Cremona wrote: 
>> >> >> 
>> >> >> On 17 April 2014 01:55, Irene <irene....@gmail.com> wrote: 
>> >> >> > Hello! 
>> >> >> > 
>> >> >> > I want to define a polynomial that I know lies in GF(p^2,'b')[x], 
>> >> >> > p=3700001. 
>> >> >> > The problem is that I have to define it as a product 
>> >> >> > E=(X-a_1)*(X-a_2)*(X-a_3)*(X-a_4)*(X-a_5)*(X-a_6), where every 
>> a_j is 
>> >> >> > in 
>> >> >> > GF(p^13,'a')[X]. 
>> >> >> > I tried to do GF(p^2,'b')[x](E), but then Sage just changes the 
>> >> >> > generator 
>> >> >> > 'a' and writes the same expression with the generator 'b'. 
>> >> >> > Any idea about how to do this? 
>> >> >> > Thank you!! 
>> >> >> 
>> >> >> Did you write that correctly?  GF(p^13) is not an extension of 
>> >> >> GF(p^2).  If a1 is in GF(p^13) then a1.minpoly() will give its min 
>> >> >> poly, in GF(p)[x]. 
>> >> >> 
>> >> >> John Cremona 
>> >> >> 
>> >> >> > 
>> >> >> > -- 
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