Hi guys,
This is so simple that probably someone else has already noticed it, but
just in case:
sage: x,t = var('x,t')
sage: f = (1-x)/(1-x*cos(t))
sage: f(x=1)
0
sage: f(t=0)(x=1)
1
The second one is, of course, the correct answer. (FYI, Mathematica9 fails,
too.)
Wouldn't the first one return some sort of conditional expression: "if t=0
then 1, else 0"
I would be happy to help in the debugging, if I can get some indication of
what is running in the background, i.e. what function is called when one
does the substitution "f(x=1)".
Cheers,
Jesús Torrado
--
You received this message because you are subscribed to the Google Groups
"sage-support" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to sage-support+unsubscr...@googlegroups.com.
To post to this group, send email to sage-support@googlegroups.com.
Visit this group at http://groups.google.com/group/sage-support.
For more options, visit https://groups.google.com/d/optout.
