Hello !

 (it seems like is_connected should really only be used for undirected 
> graphs).
>

It is useful from time to time in digraphs too. Sometimes you cannot split 
a DiGraph problem into one sub-problem for each strongly connected 
component, yet it is possible if you consider independently the 'connected 
components of the underlying graph'.

This being said, if you think that it could confuse other persons you could 
add some [note/longer explanation] in the documentation of 
GenericGraph.is_connected. This could clearly be made clearer, with a 
pointer toward `is_strongly_connected` for instance.

Nathann

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