> No more assumptions are required to integrate
> <http://www.wolframalpha.com/input/?i=Integrate%5Bx%5E%28s+-+1%29%2F%28e%5Ex+%2B+1%29%2C+%7Bx%2C+0%2C+Infinity%7D%5D+>
> .
>
More interestingly,
(%i1) assume(s>0);
(%o1) [s > 0]
(%i3) integrate(x^(s - 1)/(%e^x+1),x,0, inf);
Is s an integer?
yes;
inf
/ s - 1
[ x
(%o3) I ------- dx
] x
/ %e + 1
0
(%i4) integrate(x^(s - 1)/(%e^x+1),x,0, inf);
Is s an integer?
n;
inf
/ s - 1
[ x
(%o4) I ------- dx
] x
/ %e + 1
0
See https://sourceforge.net/p/maxima/bugs/2969/
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