On Thursday, November 5, 2015 at 5:11:42 PM UTC-8, Rob Beezer wrote: > > LIke I said, my complex analysis is rusty. And I am really asking for > somebody else. Is the chunk of code that produces 2 (above) not following > the definition of the residue? >
No it's not. If t=1/z then you don't get a truncated taylor expansion around t=0 by substituting t=1/z in the taylor expansion around z=0. In general, if you define the residue by a contour integral, then the residue of exp(1/z) around z=0 is 0: Any contour around z=0 is a boundary of a simply connected domain of the Riemann sphere on which the function is regular, so integrating along the contour gets you 0. exp(1/z) has an essential singularity at z=0, so there is no laurent expansion to read off the residue from. -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
