Le mardi 24 mai 2016 16:03:55 UTC+2, Michael Orlitzky a écrit : > > > If you're sure that every expression involved is real, that's still the > correct answer, because x == 0. If sqrt(x) or sqrt(-x) might not be > real, you're going to get nonsense calling simplify_real() on them. > > Yes, I think this is the very spirit of this simplify_real() function: it gives standard results for real expressions, with sqrt considered as a bijective map R+ --> R+, whose inverse is R+ --> R+, x |--> x^2. Another example of good behavior of simplify_real():
sage: assume(x<0) sage: sqrt(x^2).simplify_real() -x Best regards, Eric. -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at https://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
