So... I couldn't really follow: should I open a new ticket, or should it be 
solved by integrating the new maxima?

On Sunday, 22 January 2017 19:37:50 UTC+2, Dima Pasechnik wrote:
>
>
>
> On Sunday, January 22, 2017 at 4:13:53 PM UTC, William wrote:
>>
>> On Sun, Jan 22, 2017 at 7:14 AM, Peleg Michaeli <free...@gmail.com> 
>> wrote: 
>> > Hi, 
>> > 
>> > sage: ((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x)).limit(x=infinity) 
>> > -Infinity 
>> > 
>> > This is a wrong answer. It should be 2. 
>> > 
>> > Replacing 3/2 in the power by 1, 2, or 3 (at least) gives correct 
>> answers 
>> > (2, inf, inf).  Replacing it by 5/2 given a wrong answer again. 
>> > 
>> > Is this related to a known bug? 
>>
>> I don't know if it is known - - you can try searching 
>> https://trac.sagemath.org/, which lists all bugs we know of. 
>>
>> This is actually a bug in **MAXIMA**, which Sage calls to do this 
>> limit: http://maxima.sourceforge.net/ 
>>
>
> no, it's not in Maxima 5.39.0 (see https://trac.sagemath.org/ticket/18920 
> and give it a positive review :-))
> called with its default settings.
>
> $ sage --maxima
> ;;; Loading #P"/home/dima/Sage/sage-dev/local/lib/ecl/sb-bsd-sockets.fas"
> ;;; Loading #P"/home/dima/Sage/sage-dev/local/lib/ecl/sockets.fas"
> ;;; Loading #P"/home/dima/Sage/sage-dev/local/lib/ecl/defsystem.fas"
> ;;; Loading #P"/home/dima/Sage/sage-dev/local/lib/ecl/cmp.fas"
> Maxima 5.39.0 http://maxima.sourceforge.net
> using Lisp ECL 16.1.2
> Distributed under the GNU Public License. See the file COPYING.
> Dedicated to the memory of William Schelter.
> The function bug_report() provides bug reporting information.
> (%i1) limit((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x),x,inf);
> (%o1)                                  2
>
> Although calling this version of Maxima as  
> sage: ((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x)).limit(x=infinity)
>
> gives -Infinity, still, as it's not called with default settings, but with 
> something
> that breaks it sometimes.
>
>
>> If you call sympy instead it gets the right answer: 
>>
>> sage: ((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x)).limit(x=infinity, 
>> algorithm="sympy") 
>> 2 
>>
>> sage: ((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x)).limit(x=infinity, 
>> algorithm="maxima_taylor") 
>> -Infinity 
>>
>> sage: ((2^(2*x+1)+(2^x*x^100)^(3/2))/(4^x-100*2^x)).limit(x=infinity, 
>> algorithm="maxima") 
>> -Infinity 
>>
>>
>>
>> > 
>> > 
>> > Thanks, 
>> > Peleg. 
>> > 
>> > -- 
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>>
>>
>>
>> -- 
>> William (http://wstein.org) 
>>
>

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