Not directly, but it shouldn't be hard to just keep track of which vertex
sets you have seen so far. Eg.
seen = {}
for p in g.subgraph_search_iterator(graphs.PathGraph(3, induced=True)):
vxs = tuple(sorted(p))
if vxs not in seen:
seen[vxs]=True
print vxs
Note that you should include induced=True in the call to
subgraph_search_iterator, since induced is False by default.
On Thursday, July 27, 2017 at 4:42:18 AM UTC-4, Selvaraja S wrote:
>
> Thanks for the response.
>
> sage: g=Graph(d)
> sage: for p in g.subgraph_search_iterator(graphs.PathGraph(3)):
> print(p)
>
> This is giving the all the paths of length 3. But I have one more question.
>
> Suppose $xyz$ is induced path of length 3. Note that $zyx$ is also induced
> path of length.
> Can I avoid this path?
>
>
>
> On Thursday, July 27, 2017 at 12:07:04 PM UTC+5:30, fidelbc wrote:
>>
>> Yes we can. Suppose the path has length k and thus k+1 vertices. Then the
>> following command returns an iterator over all lists of vertices that
>> induce paths on k+1 vertices in G.
>>
>> G.subgraph_search_iterator(graphs.PathGraph(k+1),induced=True)
>>
>> More on this may be found at [1].
>>
>> [1];
>> http://doc.sagemath.org/html/en/reference/graphs/sage/graphs/generic_graph.html#sage.graphs.generic_graph.GenericGraph.subgraph_search_iterator
>>
>> On Thursday, July 27, 2017 at 12:37:31 AM UTC-4, Selvaraja S wrote:
>>>
>>> Let $G$ be a finite simple graph.
>>> Can we find all paths(induced ) of given length?
>>>
>>>
>>> Thanks in advance.
>>>
>>>
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