Sorry, I just noticed that A+B works. What about intersections? A*B does not seem to be implemented.
On Thu, 13 Jan 2022 at 03:05, G. M.-S. <lists....@gmail.com> wrote: > > Hello. > > Is it possible to define a binary operation ∪ such that > A ∪ B > gives > A.union(B) > with the latter taking care of all problems (not a Set, etc.)? > > And if so, would it be possible to have an n-ary operation (n > 1) such > that for instance > A ∪ B ∪ C > gives > A.union(B).union(C) > without having to write (A ∪ B) ∪ C ? > > Guillermo > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sage-support/CANnG18_Y8E1B8hgSRnB2Xv_vtr%2BjWspG-J546CwH4_CFeNTbvQ%40mail.gmail.com.
