I installed scalr_tools (Python 2.6 / easy_install scalr). I successfully added the configuration with the URL to my opensource installation. The output of the configure command:
+------------+-------------------------------+ | setting | value | +------------+-------------------------------+ | url | https://someurl | | access key | somekey | | key id | someid | | version | 2.3.0 | +------------+-------------------------------+ However whenever I try any command, the result is: [root@xyz ~]# scalr list-farms Cannot parse XML. ['not well-formed (invalid token): line 45, column 67'] The output is the same irrespective of which command I try. Help! Thanks Srini -- You received this message because you are subscribed to the Google Groups "scalr-discuss" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/scalr-discuss?hl=en.
