Please provide output of `scalarizr -v` .

Thanks,
Igor

On 26 June 2012 11:34, Pawel Kilian <[email protected]> wrote:
> Hi.
> I see this error again...
> 2012-06-26 14:24:54,032 - ERROR - scalarizr - Request failed. HTTP Error
> 500: Error. URL: https://scalr.nellymoser.com/query-env. Service message:
> Version '2012-04-17' not supported
> Traceback (most recent call last):
>   File "/usr/lib/python2.6/site-packages/scalarizr/__init__.py", line 801,
> in main
>     cnf.fire('apply_user_data', cnf)
>   File "/usr/lib/python2.6/site-packages/scalarizr/libs/pubsub.py", line 26,
> in fire
>     ln(*args, **kwargs)
>   File "/usr/lib/python2.6/site-packages/scalarizr/__init__.py", line 365,
> in _apply_user_data
>     userdata = queryenv.get_server_user_data()
>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line 126,
> in get_server_user_data
>     return self._request('get-server-user-data', {},
> self._read_get_server_user_data_response)
>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line 192,
> in _request
>     xml = self.fetch(command, **params)
>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line 70, in
> fetch
>     response = opener.open(req)
>   File "/usr/lib64/python2.6/urllib2.py", line 397, in open
>     response = meth(req, response)
>   File "/usr/lib64/python2.6/urllib2.py", line 510, in http_response
>     'http', request, response, code, msg, hdrs)
>   File "/usr/lib64/python2.6/urllib2.py", line 435, in error
>     return self._call_chain(*args)
>   File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain
>     result = func(*args)
>   File "/usr/lib64/python2.6/urllib2.py", line 518, in http_error_default
>     raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
> QueryEnvError: Request failed. HTTP Error 500: Error. URL:
> https://scalr.nellymoser.com/query-env. Service message: Version
> '2012-04-17' not supported
>
>
>
> [root@ec2-107-22-134-217 hosts]# rpm -qa | grep scal
> scalr-upd-client-0.2.r151-1.el5
> scalarizr-base-0.9.r3625-1.el5
> scalarizr-0.6.25-1.el5
> scalarizr-ec2-0.9.r3625-1.el5
>
>
>
> I still use scalar 2.2.0
>
> and latest scalarizr
>
> On Wednesday, May 30, 2012 11:07:35 AM UTC-4, Pawel Kilian wrote:
>>
>> 2012-05-30 10:51:35,457 - ERROR - scalarizr.handlers - Request failed.
>> HTTP Error 500: Error. URL: https://scalr.nellymoser.com/query-env.
>> Service message: Version '2012-04-17' not supported
>> Traceback (most recent call last):
>>   File "/usr/lib/python2.6/site-packages/scalarizr/handlers/
>> __init__.py", line 301, in __call__
>>     handler(message)
>>   File "/usr/lib/python2.6/site-packages/scalarizr/handlers/
>> script_executor.py", line 213, in __call__
>>     target_ip=target_ip, local_ip=local_ip)
>>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line
>> 147, in list_scripts
>>     return self._request("list-scripts",parameters,
>> self._read_list_scripts_response)
>>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line
>> 193, in _request
>>     xml = self.fetch(command, **params)
>>   File "/usr/lib/python2.6/site-packages/scalarizr/queryenv.py", line
>> 70, in fetch
>>     response = opener.open(req)
>>   File "/usr/lib64/python2.6/urllib2.py", line 397, in open
>>     response = meth(req, response)
>>   File "/usr/lib64/python2.6/urllib2.py", line 510, in http_response
>>     'http', request, response, code, msg, hdrs)
>>   File "/usr/lib64/python2.6/urllib2.py", line 435, in error
>>     return self._call_chain(*args)
>>   File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain
>>     result = func(*args)
>>   File "/usr/lib64/python2.6/urllib2.py", line 518, in
>> http_error_default
>>     raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
>> QueryEnvError: Request failed. HTTP Error 500: Error. URL:
>> https://scalr.nellymoser.com/query-env. Service message: Version
>> '2012-04-17' not supported
>>
>>
>>
>> so it looks like my version of scalr does not support 2012-04-17 api
>>
>> is there a way that i can fix it temporarly?
>
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