What should be the result of (infinite? +nan.0+inf.0i)?
The report says #t but that seems undesirable, because
it would mean that finite?/infinite?/nan? would no
longer be a partitioning of the complex numbers,
since both nan? and infinite? are true.
The wording is "The infinite? procedure returns #t ...
on complex numbers if their real and imaginary parts
or both are infinite". I think we should add "and
neither is +nan.0"".
(I wouldn't find a link to the errata page.)
--
--Per Bothner
[email protected] http://per.bothner.com/
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