Dictionaries do not have duplicate keys (labels). You could only make a
list of datawithLabelX for each key label. But what is the benefit of this?
Philipp
Am 05.04.2013 11:37, schrieb Bill Power:
> i know this is going to sound a little silly, but I was thinking there
> that it might be nice to be able to do this with scikit learn
>
> clf = sklearn.anyClassifier()
> clf.fit( { 0: dataWithLabel0,
> 1: dataWithLabel1 } )
>
> instead of having to separate the data/labels manually. i guess fit
> would do that internally, but it might be nice to have this
>
> bill
>
>
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