"Pagliari, Roberto" <[email protected]>
wrote:
 
> If that's the case, why is that the underlying implementation of k-means
> does not take this into account?

Because then it would be the "classification EM algorithm" (often called
CEM) instead of k-means. By definition, k-means is CEM constrained with
equal cluster size and equal and spherical covariance matrices. 

Sturla


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