What if I do need to use CrawlSpider? After all I *was* using the Rule 
functionality, plus several other things that are needed in my script and 
that I cannot pass as simple arguments to "scrapy crawl xxx"?
Thanks!
Michele C

Il giorno mercoledì 5 novembre 2014 10:15:31 UTC-5, Travis Leleu ha scritto:
>
> I would recommend not using the CrawlSpider class if you're not using the 
> Rule functionality.  Just use a normal scrapy.Spider, and then override the 
> parse() class like you said (then obviously you have to build the logic to 
> identify the links to follow).
>
> When you're writing your parse function, one neat thing: you can yield 
> items, and they get processed through the item pipeline, or you can yield 
> requests, and they get added to the request queue.
>
>
> On Wed, Nov 5, 2014 at 7:02 AM, Michele Coscia <[email protected] 
> <javascript:>> wrote:
>
>> Ok, but where? In the CrawlSpider? Should I  basically override the 
>> parse() function? Can I still use my rule in there, and if so, how?
>> Thanks!
>> Michele C
>>
>> Il giorno mercoledì 5 novembre 2014 09:55:28 UTC-5, Aru Sahni ha scritto:
>>>
>>> You can just invoke BeautifulSoup as one normally would and not use 
>>> Scrapy's built-in functionality.
>>>
>>> ~A
>>>
>>> On Wed, Nov 5, 2014 at 9:51 AM, Michele Coscia <[email protected]> 
>>> wrote:
>>>
>>>> Bingo, that's it, you are great.
>>>> So it is what exits from the Selector(response) that is the problem, 
>>>> because response contains the entire malformed html (as it should).
>>>>
>>>> I tried a little test, feeding the malformed html to Beautiful soup: 
>>>> lxml parser still fails, html5lib instead parses correctly. So, the 
>>>> question is: how do I use html5lib's parser instead of lxml in Scrapy? The 
>>>> documentation 
>>>> <http://doc.scrapy.org/en/latest/faq.html#how-does-scrapy-compare-to-beautifulsoup-or-lxml>
>>>>  
>>>> tells me that "you can easily use BeautifulSoup 
>>>> <http://www.crummy.com/software/BeautifulSoup/> (or lxml 
>>>> <http://lxml.de/>) instead", but it doesn't say how :-)
>>>>
>>>> Finally: I'd dare to say that this is a bug and it should be reported 
>>>> as such. If any browser and html5lib can parse the page, then so should 
>>>> Scrapy. Do you think I should submit it on the Github page?
>>>>
>>>> Thanks, you have been already very helpful!
>>>> Michele C
>>>>
>>>>
>>>>
>>>>
>>>> Il giorno mercoledì 5 novembre 2014 06:20:26 UTC-5, Rocío Aramberri ha 
>>>> scritto:
>>>>>
>>>>> Hi Michele,
>>>>>
>>>>> I've been investigating further in your problem and looks like the 
>>>>> html in http://www.mass.gov/eea/agencies/dfg/der/ is malformed.  You 
>>>>> can see here what part of the html is really reaching extract_links: 
>>>>> http://pastebin.com/6kTT5Amt (there is an </html> at the end of it). 
>>>>> This page has 4 html definitions.
>>>>>
>>>>> Hope this helps,
>>>>> Kind Regards,
>>>>> Rocio
>>>>>
>>>>> On Tue Nov 04 2014 at 8:53:36 PM Michele Coscia <[email protected]> 
>>>>> wrote:
>>>>>
>>>>>>
>>>>>> By doing some debugging in ipdb I found out that the extract_links 
>>>>>> function in the class LxmlLinkExtractor is not getting the same data 
>>>>>> I see in the scrapy shell. While in the scrapy shell I see the correct 
>>>>>> data 
>>>>>> inside the <body> tag, when I see at the html variable in extract_links 
>>>>>> I see:
>>>>>>
>>>>>> \r\n\t\t<a id="top"></a>\r\n\t\t\t<!-- alert content here -->\t\t\t
>>>>>>
>>>>>> I *know* that both the scrapy shell and my script are getting the 
>>>>>> very same data from the server (checked with wireshark). So somewhere in 
>>>>>> between the fetching of the data and the extract_links function, the 
>>>>>> content of the body disappears.
>>>>>>
>>>>>> Someone with knowledge about the source code can tell me which 
>>>>>> function calls LxmlLinkExtractor's extract_links?
>>>>>>
>>>>>> Thanks!
>>>>>> Michele C
>>>>>>
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