Re: [algogeeks] DeShaw Question....tough One

2010-09-06 Thread vignesh radhakrishnan
http://en.wikipedia.org/wiki/Longest_increasing_subsequence

On 6 September 2010 14:01, bittu shashank7andr...@gmail.com wrote:

 u are given an array and u have to print the longest increasing
 scattered subsequence...eg..{11,9,8,2,10,7,3,4,5}.


 Solve it O(n);


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Re: [algogeeks] String Problems

2010-05-20 Thread vignesh radhakrishnan
@Marcio, I get your algo now. So a substring match is also a match.  I get
your approach. Thank you.
Any ideas for the second problem?

On 20 May 2010 10:45, vignesh radhakrishnan rvignesh1...@gmail.com wrote:

 @Mario Your estimate of no. of strings, I guess doesn't consider strings of
 length less than length H or W.
 it would order(4H^2+4W^2) approximately.

 I guess I 've understood it right. correct me if I'm wrong


 On 20 May 2010 07:23, Mario Ynocente Castro ycma...@gmail.com wrote:

 I don't think 1014 needs any special algorithm, if we've got an H x W
 matrix, then we've got (4H+4W-2) strings in which you must look, and you can
 do this with a greedy strategy.

 2010/5/19 vignesh radhakrishnan rvignesh1...@gmail.com

  I'm trying to solve some string problems somewat efficiently. Can
 someone tell me what would be efficient DS for solving these problems
 http://acm.jlu.edu.cn/joj/showproblem.php?pid=1014
 http://acm.jlu.edu.cn/joj/showproblem.php?pid=1873

 Thanks,
 Regards,
 Vignesh
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Re: [algogeeks] String Problems

2010-05-20 Thread vignesh radhakrishnan
@Mario Your estimate of no. of strings, I guess doesn't consider strings of
length less than length H or W.
it would order(4H^2+4W^2) approximately.

I guess I 've understood it right. correct me if I'm wrong

On 20 May 2010 07:23, Mario Ynocente Castro ycma...@gmail.com wrote:

 I don't think 1014 needs any special algorithm, if we've got an H x W
 matrix, then we've got (4H+4W-2) strings in which you must look, and you can
 do this with a greedy strategy.

 2010/5/19 vignesh radhakrishnan rvignesh1...@gmail.com

 I'm trying to solve some string problems somewat efficiently. Can someone
 tell me what would be efficient DS for solving these problems
 http://acm.jlu.edu.cn/joj/showproblem.php?pid=1014
 http://acm.jlu.edu.cn/joj/showproblem.php?pid=1873

 Thanks,
 Regards,
 Vignesh
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[algogeeks] String Problems

2010-05-19 Thread vignesh radhakrishnan
I'm trying to solve some string problems somewat efficiently. Can someone
tell me what would be efficient DS for solving these problems
http://acm.jlu.edu.cn/joj/showproblem.php?pid=1014
http://acm.jlu.edu.cn/joj/showproblem.php?pid=1873

Thanks,
Regards,
Vignesh
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Re: [algogeeks] Convert a Binary tree into spike.

2010-05-13 Thread vignesh radhakrishnan
do bfs.

On 13 May 2010 09:18, vinayan c vinayan1...@gmail.com wrote:

 Something like this
1
2   3
  4 5 67


  1
  |
  2-3
  |
  4-5-6-7




























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Re: [algogeeks] compute kth smallest element from union of two lists

2010-05-13 Thread vignesh radhakrishnan
This is for kth largest. Change it for kth smallest

In fact, this problem is amenable to something very similar to binary
search. Suppose my arrays are A and B. The idea is to keep track of two
indices, a (for A) and b (for B), such that a + b = k - 1 (it's very
important to maintain this invariant). It's easy to check whether A[a] or
B[b] is the answer: A[a] is the answer if and only if

B[b-1] = A[a] = B[b],

and B[b] is the answer if and only if

A[a-1] = B[b] = A[a],

where we use the convention that A[-1] = B[-1] = negative infinity. (This
can be determined in constant time.) Moreover, if neither of these is the
case, you can divide the problem in half: if A[a]  B[b-1], you restrict
your attention to the portion of A above index a and the portion of B below
index b, and otherwise (it must be the case that B[b]  A[a-1]), you
restrict your attention to the portion of A below index a and the portion of
B above index b. (If you start with a and b in the middle of the arrays and
always make the new indices be in the middle of the subarrays you're
considering at that point, this step will always divide the problem in
half.)
Thanks to Lux Perpetua http://forums.devshed.com/member.php?u=74699
source:
http://forums.devshed.com/software-design-43/finding-kth-largest-element-in-a-union-of-two-arrays-137322.html

On 13 May 2010 19:34, divya sweetdivya@gmail.com wrote:

 You are given two sorted lists of size m and n. Give an O(log m+log n)
 time algorithm for computing the kth smallest element in the union of
 the two lists

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Re: [algogeeks] 400!

2010-05-03 Thread vignesh radhakrishnan
@siddharth and prasoon either design a very long integer library yourself,
or use gmp library in cpp or BigInteger Class in java.

Regards,
vignesh

On 3 May 2010 09:46, siddharth srivastava akssps...@gmail.com wrote:

 But is there any way to accomplish this without an array ? Even for 100!.


 On 2 May 2010 06:15, Prasoon Mishra prasoonbluel...@gmail.com wrote:

 I think challenge here is not the Execution time, but the storage. 300 !
 or 400! should generally go beyond the storage capabilities of long long
 ints in cpp.
 @ Rohit Saraf: Hence, I don't know if even tail recursion will ultimately
 be able to store the output.
 I think Rajesh Patidar's answer fits the bill well, in terms of storage.


 On Sun, May 2, 2010 at 2:23 PM, vignesh radhakrishnan 
 rvignesh1...@gmail.com wrote:

 I agree with abhijith. But given some very large x for which i would have
 to find factorial.
 I would either
 (i) use gmp in cpp or BigInteger or java if its not a lab exercise or an
 interview
 (ii) use simple brute multiplication algorithm.
 The second approach requires
  (a) The no. of digits in n! for making storage available
  (b) The calculation itself which I would brute force

 References:

 http://inder-gnu.blogspot.com/2009/08/find-number-of-digits-in-factorial-of.html

 http://stackoverflow.com/questions/1113167/can-one-know-how-large-a-factorial-would-be-before-calculating-it
 http://delphiforfun.org/programs/big_factorials.htm



 On 2 May 2010 13:59, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:

 google it... u will gt it

 i am on mobile... cannot explain now..

 On 5/2/10, divya jain sweetdivya@gmail.com wrote:
  wat is tail recursion plz explan in detail
 
  On 2 May 2010 08:15, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:
 
  @divya use tail recursion and rest should be fine..
 
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Re: [algogeeks] a google question

2010-05-02 Thread vignesh radhakrishnan
@divya You're rite. Post a solution if you have one.

--
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On 2 May 2010 13:14, divya jain sweetdivya@gmail.com wrote:

 @Mohit

 according to ur algo if a[1], b[0] has sum greater than a[0],b[1]
 then i is incremented   i is now 2 so for next iteration u ll compare a[2]
 b[0] and a[1] b1]. but what about a[0] b[1] this pair s lost forever. think
 for ths case also.


 On 2 May 2010 11:22, mohit ranjan shoonya.mo...@gmail.com wrote:

 @Algoose Chase

 point taken
 Thanks


 Mohit Ranjan
 Samsung India Software Operations.


 On Sat, May 1, 2010 at 8:43 PM, Algoose Chase harishp...@gmail.comwrote:

 @mohit

 The idea of DP is fine.
 When you find the Max i dont think you need to include A[i+1]+B[j+1]
 because it can never be greater than both A[i+1]+B[j] and A[i]+B[j+1] since
 both the lists are sorted in decreasing order.


 On Fri, Apr 30, 2010 at 8:47 PM, mohit ranjan 
 shoonya.mo...@gmail.comwrote:

 oops

 Sorry didn't read properly
 last algo was for array sorted in ascending order

 for this case, just reverse the process


 A[n] and B[n] are two array

 loop=n, i=0, j=0;


 while(loop0)  // for n largest pairs
 {
   print A[i]+B[j];  // sum of first index from both array will
 be max

   foo = MAX ( A[i+1]+B[j], A[i+1]+B[j+1], A[i]+B[j+1] ) // using DP,
 moving forward

   if foo==A[i+1]+B[j]; i++   // only increment A
   if foo==A[i+1]+B[j+1]; i++; j++   // increment both A and B
   if foo==A[i]+B[j+1]; j++  // increment only B

 }



 Mohit Ranjan
 Samsung India Software Operations.


 On Fri, Apr 30, 2010 at 8:40 PM, mohit ranjan 
 shoonya.mo...@gmail.comwrote:

 Hi Divya,


 A[n] and B[n] are two array

 loop=n, i=n-1, j=n-1;

 while(loop0)  // for n largest pairs
 {
   print A[i]+B[j];  // sum of last index from both array will
 be max

   foo = MAX ( A[i-1]+B[j], A[i-1]+B[j-1], A[i]+B[j-1] ) // using DP
 moving backward

   if foo=A[i-1]+B[j]; i--   // only reduce A
   if foo=A[i-1]+B[j-1]; i--; j--   // reduce both A and B
   if foo=A[i]+B[j-1]; j--  // reduce only B
 }

 Time: O(n)


 Mohit Ranjan



 On Fri, Apr 30, 2010 at 5:35 PM, divya sweetdivya@gmail.comwrote:

 Given two sorted postive integer arrays A(n) and B(n) (W.L.O.G, let's
 say they are decreasingly sorted), we define a set S = {(a,b) | a \in
 A
 and b \in B}. Obviously there are n^2 elements in S. The value of such
 a pair is defined as Val(a,b) = a + b. Now we want to get the n pairs
 from S with largest values. The tricky part is that we need an O(n)
 algorithm.

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Re: [algogeeks] 400!

2010-05-02 Thread vignesh radhakrishnan
I agree with abhijith. But given some very large x for which i would have to
find factorial.
I would either
(i) use gmp in cpp or BigInteger or java if its not a lab exercise or an
interview
(ii) use simple brute multiplication algorithm.
The second approach requires
 (a) The no. of digits in n! for making storage available
 (b) The calculation itself which I would brute force

References:
http://inder-gnu.blogspot.com/2009/08/find-number-of-digits-in-factorial-of.html
http://stackoverflow.com/questions/1113167/can-one-know-how-large-a-factorial-would-be-before-calculating-it
http://delphiforfun.org/programs/big_factorials.htm


On 2 May 2010 13:59, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:

 google it... u will gt it

 i am on mobile... cannot explain now..

 On 5/2/10, divya jain sweetdivya@gmail.com wrote:
  wat is tail recursion plz explan in detail
 
  On 2 May 2010 08:15, Rohit Saraf rohit.kumar.sa...@gmail.com wrote:
 
  @divya use tail recursion and rest should be fine..
 
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  http://www.cse.iitb.ac.in/~rohitfeb14http://www.cse.iitb.ac.in/%7Erohitfeb14
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Re: [algogeeks] Divide and Conquer problem

2010-04-08 Thread vignesh radhakrishnan
You 've got n teams and nC2 ways of conducting the matches with specified
constraints
that's n/2(n-1). So, each day you need to conduct n/2 matches such that, no
team repeats within a day, no match that was previously held repeats. Since
the problem has an unique solution, you can either brute force it with a
program or design an back track solution.

regards,
vignesh
On 7 April 2010 12:20, «« ÄÑÜJ »» anujlove...@gmail.com wrote:

 Can any one help me with this problem


 Its a divide and conquer problem where, there are n teams and each
 team plays each opponent only once. And each team plays exactly once
 every day. If n is the power of 2, I need to construct a timetable
 allowing the tournament to finish in n-1 days...

 Any help would be appreciated.. thanks

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Re: [algogeeks] Cartesian Product in set theory

2010-02-09 Thread vignesh radhakrishnan
The unordered pair will be a subset of cartesian product. What is the
significance of it?

On 8 February 2010 21:18, pinco1984 paris...@gmail.com wrote:

 Hi all,

 I have came across a problem and I am not aware if there is such a
 thing in set theory and if so what is it called.

 Mainly I have several sets that I am interested in their cartesian
 product. But this cartesian product should not be a set of ordered
 pairs but a set of sets. Basically unordered pairs.

 I wonder if this concept is well defined and what is it called.

 Thanks.
 P.

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