[android-developers] Re: Why String \0 is converted to [65533,65533]
On Nov 14, 5:58 am, Joes joyj...@gmail.com wrote: While I'm programming the Android SMTP code,I met a confused problem with code similar as the following: String str= \0 username \0 passwrd; After executed the code, I found \0 is intepreted as two undisplayable char. I ran a quick test and saw (as others have) that this returns a single- character string with one character (0), as expected. (Stretching) if you converted the string to a UTF-8 byte array, you would see two bytes (0xc0 0x80) due to the way that Java specifies its modified UTF-8; see e.g. http://java.sun.com/javase/6/docs/technotes/guides/jni/spec/types.html#wp16542 . However, I don't see how you would get to something like 65533 (-3) from there. -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Why String \0 is converted to [65533,65533]
I assume that this is Java code and not C code. Is that right? Are you sure that you posted your code correctly? When I try what you've done, I get an IndexOutOfBoundsException when executing sZero.charAt(1), which is what I would expect. Also, are you sure you're getting 65533 and not 65535? If you convert a value of -1 to an unsigned 16-bit integer, you get 65535. If you don't understand why, search the web for how negative integers are stored at the bit level. So, this might be related. Also, it sounds like you want to control things at the byte level. If so, you probably want to use the byte data type and stay away from char and int and String. Don't think of a String as an array of bytes, because it's not (in Java). It's more list a list of characters WHERE each character might actually take up more than one byte because of internationalization support. So perhaps you should be working with byte instead of char, assuming you're trying to manipulate things at the byte level. -- PJ On Nov 14, 9:42 am, Joes joyj...@gmail.com wrote: I just wanna know, with what condition can cause this issue. I think it's probably because of the charset setup which is controlled by makefile or something else. I need a direction to look into. Thanks On Nov 14, 9:18 am, Andrei gml...@gmail.com wrote: just a guess that u want to do this instead \\0 On Nov 14, 8:58 am, Joes joyj...@gmail.com wrote: All, While I'm programming the Android SMTP code,I met a confused problem with code similar as the following: String str= \0 username \0 passwrd; After executed the code, I found \0 is intepreted as two undisplayable char. Then I executed the folloing debug code: String sZero = \0; int iLen = sZero.length(); int iValue1 = (int)sZero.charAt(0); int iValue2 = (int)sZero.charAt(1); Log.w(ZERO, Zero String, Lenth=, iLen, value1=, iValue1, value2=, iValue2); What I get in screen is : Zero String, Length=2 value1=65533 value2=65533. Really confuse me, why \0 become [65533,65533] in my program? Thanks- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Why String \0 is converted to [65533,65533]
just a guess that u want to do this instead \\0 On Nov 14, 8:58 am, Joes joyj...@gmail.com wrote: All, While I'm programming the Android SMTP code,I met a confused problem with code similar as the following: String str= \0 username \0 passwrd; After executed the code, I found \0 is intepreted as two undisplayable char. Then I executed the folloing debug code: String sZero = \0; int iLen = sZero.length(); int iValue1 = (int)sZero.charAt(0); int iValue2 = (int)sZero.charAt(1); Log.w(ZERO, Zero String, Lenth=, iLen, value1=, iValue1, value2=, iValue2); What I get in screen is : Zero String, Length=2 value1=65533 value2=65533. Really confuse me, why \0 become [65533,65533] in my program? Thanks -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
[android-developers] Re: Why String \0 is converted to [65533,65533]
I just wanna know, with what condition can cause this issue. I think it's probably because of the charset setup which is controlled by makefile or something else. I need a direction to look into. Thanks On Nov 14, 9:18 am, Andrei gml...@gmail.com wrote: just a guess that u want to do this instead \\0 On Nov 14, 8:58 am, Joes joyj...@gmail.com wrote: All, While I'm programming the Android SMTP code,I met a confused problem with code similar as the following: String str= \0 username \0 passwrd; After executed the code, I found \0 is intepreted as two undisplayable char. Then I executed the folloing debug code: String sZero = \0; int iLen = sZero.length(); int iValue1 = (int)sZero.charAt(0); int iValue2 = (int)sZero.charAt(1); Log.w(ZERO, Zero String, Lenth=, iLen, value1=, iValue1, value2=, iValue2); What I get in screen is : Zero String, Length=2 value1=65533 value2=65533. Really confuse me, why \0 become [65533,65533] in my program? Thanks- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Android Developers group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
