Re: [android-developers] How to stop terminate the Android application when using the native code

[Justin Anderson]

>
> I know, i can disable it, so it will work, but i'd like to let the app can
> run many times again. So i disable the exit(), but when call the second
> times, it generates errors.
>
> Could you help?
>
Debug your code, find the cause of the errors, and fix them...

Thanks,
Justin Anderson
MagouyaWare Developer
http://sites.google.com/site/magouyaware


On Fri, Jul 20, 2012 at 12:58 AM, Clark kent  wrote:

> I know, i can disable it, so it will work, but i'd like to let the app can
> run many times again. So i disable the exit(), but when call the second
> times, it generates errors.
>
> Could you help?
>
> Thanks
> Clark
>
>
> On Sunday, July 15, 2012 5:52:38 AM UTC+7, Dianne Hackborn wrote:
>>
>> You just need to fix your native code so it doesn't do this.  Anyone
>> giving you a native library that is calling exit() in it is an evil sadist.
>> :p
>>
>> On Fri, Jul 13, 2012 at 3:02 AM, Clark kent wrote:
>>
>>> Hello every body
>>>
>>> I have this problem which can not resolve it.
>>>
>>> I'm calling the native code(*C code*) from the android application. But
>>> in the native code, they call function "*exit(0)*" so it makes the app
>>> on Android terminate. Could any one know how to stop this one, because
>>> after i called one method from native code , after it finished, it will
>>> terminate the Android application.
>>>
>>> I found a way is disable the method "*exit(0)*", so it will not
>>> terminate the Android app, but it meet error when i called the native
>>> method second time, some error kind like this: "*Invalid heap address
>>> in internal_realloc*". I think that came from the re allocation the
>>> memory. So if any one know how to free all memory of native call, please
>>> let me know. Thanks for any comments
>>>
>>> Thanks
>>>
>>> Clark
>>>
>>> --
>>> You received this message because you are subscribed to the Google
>>> Groups "Android Developers" group.
>>> To post to this group, send email to android-developers@**
>>> googlegroups.com 
>>> To unsubscribe from this group, send email to
>>> android-developers+**unsubscr...@googlegroups.com
>>> For more options, visit this group at
>>> http://groups.google.com/**group/android-developers?hl=en
>>
>>
>>
>>
>> --
>> Dianne Hackborn
>> Android framework engineer
>> hack...@android.com
>>
>> Note: please don't send private questions to me, as I don't have time to
>> provide private support, and so won't reply to such e-mails.  All such
>> questions should be posted on public forums, where I and others can see and
>> answer them.
>>
>>  --
> You received this message because you are subscribed to the Google
> Groups "Android Developers" group.
> To post to this group, send email to android-developers@googlegroups.com
> To unsubscribe from this group, send email to
> android-developers+unsubscr...@googlegroups.com
> For more options, visit this group at
> http://groups.google.com/group/android-developers?hl=en
>

-- 
You received this message because you are subscribed to the Google
Groups "Android Developers" group.
To post to this group, send email to android-developers@googlegroups.com
To unsubscribe from this group, send email to
android-developers+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-developers?hl=en

Re: [android-developers] How to stop terminate the Android application when using the native code

[Clark kent]

I know, i can disable it, so it will work, but i'd like to let the app can 
run many times again. So i disable the exit(), but when call the second 
times, it generates errors.

Could you help?

Thanks
Clark

On Sunday, July 15, 2012 5:52:38 AM UTC+7, Dianne Hackborn wrote:
>
> You just need to fix your native code so it doesn't do this.  Anyone 
> giving you a native library that is calling exit() in it is an evil sadist. 
> :p
>
> On Fri, Jul 13, 2012 at 3:02 AM, Clark kent  wrote:
>
>> Hello every body
>>
>> I have this problem which can not resolve it. 
>>
>> I'm calling the native code(*C code*) from the android application. But 
>> in the native code, they call function "*exit(0)*" so it makes the app 
>> on Android terminate. Could any one know how to stop this one, because 
>> after i called one method from native code , after it finished, it will 
>> terminate the Android application.
>>
>> I found a way is disable the method "*exit(0)*", so it will not 
>> terminate the Android app, but it meet error when i called the native 
>> method second time, some error kind like this: "*Invalid heap address in 
>> internal_realloc*". I think that came from the re allocation the memory. 
>> So if any one know how to free all memory of native call, please let me 
>> know. Thanks for any comments
>>
>> Thanks
>>
>> Clark
>>
>> -- 
>> You received this message because you are subscribed to the Google
>> Groups "Android Developers" group.
>> To post to this group, send email to android-developers@googlegroups.com
>> To unsubscribe from this group, send email to
>> android-developers+unsubscr...@googlegroups.com
>> For more options, visit this group at
>> http://groups.google.com/group/android-developers?hl=en
>
>
>
>
> -- 
> Dianne Hackborn
> Android framework engineer
> hack...@android.com
>
> Note: please don't send private questions to me, as I don't have time to 
> provide private support, and so won't reply to such e-mails.  All such 
> questions should be posted on public forums, where I and others can see and 
> answer them.
>
>

-- 
You received this message because you are subscribed to the Google
Groups "Android Developers" group.
To post to this group, send email to android-developers@googlegroups.com
To unsubscribe from this group, send email to
android-developers+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-developers?hl=en

Re: [android-developers] How to stop terminate the Android application when using the native code

[Dianne Hackborn]

You just need to fix your native code so it doesn't do this.  Anyone giving
you a native library that is calling exit() in it is an evil sadist. :p

On Fri, Jul 13, 2012 at 3:02 AM, Clark kent  wrote:

> Hello every body
>
> I have this problem which can not resolve it.
>
> I'm calling the native code(*C code*) from the android application. But
> in the native code, they call function "*exit(0)*" so it makes the app on
> Android terminate. Could any one know how to stop this one, because after i
> called one method from native code , after it finished, it will terminate
> the Android application.
>
> I found a way is disable the method "*exit(0)*", so it will not terminate
> the Android app, but it meet error when i called the native method second
> time, some error kind like this: "*Invalid heap address in
> internal_realloc*". I think that came from the re allocation the memory.
> So if any one know how to free all memory of native call, please let me
> know. Thanks for any comments
>
> Thanks
>
> Clark
>
> --
> You received this message because you are subscribed to the Google
> Groups "Android Developers" group.
> To post to this group, send email to android-developers@googlegroups.com
> To unsubscribe from this group, send email to
> android-developers+unsubscr...@googlegroups.com
> For more options, visit this group at
> http://groups.google.com/group/android-developers?hl=en




-- 
Dianne Hackborn
Android framework engineer
hack...@android.com

Note: please don't send private questions to me, as I don't have time to
provide private support, and so won't reply to such e-mails.  All such
questions should be posted on public forums, where I and others can see and
answer them.

-- 
You received this message because you are subscribed to the Google
Groups "Android Developers" group.
To post to this group, send email to android-developers@googlegroups.com
To unsubscribe from this group, send email to
android-developers+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-developers?hl=en