"Terminated" message from kill
Hi,
This is a question similar to one from September 2006:
http://lists.gnu.org/archive/html/bug-bash/2006-09/msg00077.html
Using bash 3.2.39 on x86_64 RHEL5.2, I have a script with contents:
function bar ()
{
sleep 10 &
pid=$!
exec 3>&2 2>/dev/null
kill $pid
#usleep 1
exec 2>&3 3>&-
}
bar
If I run this script 1000 times via a loop, I get a handful of messages
(the number varies) of the form:
/path/to/script: line 14: 10327 Terminated sleep 10
If I uncomment the "usleep" line, I get no such messages at all.
If I comment out the usleep and both exec lines, I get a handful of messages.
If I then uncomment the usleep line, I get 1000 messages.
Hence, some questions:
1) Shouldn't the production of the "terminated" message be deterministic?
2) Why does sleeping make a difference?
3) Is there a "right" way to suppress the "terminated" message?
Thanks in advance.
Re: Bash prints syntax error when command in $(...) contains case-esac
> Machine Type: i686-pc-cygwin > > Bash Version: 3.2 > Patch Level: 9 > Release Status: release > > Description: > If a command in $(...) contains a case-esac construction, the > bash prints a syntax error instead > of executing the code: > bash: syntax error near unexpected token `;;' > > Repeat-By: > A simple example is: x=$(a=4; case $a in 3) echo a=3;; 4) echo a=4;; > esac) This is a long-standing problem, caused by the bash parser's requirement that parens match. Posix introduced the optional left paren before a case statement pattern list to finesse the problem, but current versions of the standard require that commands inside $(...) be parsed correctly even in the absence of balanced parens. Bash-4.0 will work as you expect, without requiring the parens to balance. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://tiswww.tis.case.edu/~chet/
Re: Bash prints syntax error when command in $(...) contains case-esac
Juergen Gohlke wrote: Description: If a command in $(...) contains a case-esac construction, the bash prints a syntax error instead of executing the code: bash: syntax error near unexpected token `;;' In case you have trouble with code you need, use this workaround: x=$(a=4; case $a in (3) echo a=3;; (4) echo a=4;; esac) And yes, I've also seen this before and I thought it was fixed - maybe I thought of something else. J.
Re: Graceful Exit
rayparrish wrote: Hello, I am writing a System Report script for Ubuntu, and even 'though I have the word exit on the last line of the script, when I run the script in terminal I have to hit enter a second time after running the script to get the terminal prompt back. I'm uploading the script, have a look and tell me how to get this thing to exit back to the terminal prompt without the second enter key press. Thanks, Ray Parrish http://www.nabble.com/file/p19598628/SystemReport.sh SystemReport.sh Hello again, I did some debugging and found that my script was choking on the line - cat | df -h >> ~/SysReport/drive.html I removed the "cat |" from the front of the command and now my script runs through and exits no problem. Thanks,. Ray Parrish of course, cat was reading from stdin, but has no input from stdin. And I have take a look at script and found that you have at some lines windows style end of lines. Maybe better you should fix it. RR
[Fwd: Re: File renaming using SED in BASH]
--- Begin Message --- MisterMuv wrote: Hi, I am having a problem renaming a files using SED. The filenames are in the following format: eg 001 - GreatPics1 (The Opening) (www.somewhere.net).jpg 002 - GreatPics2 (The Closing) (www.somewhere.net).jpg 003 - GreatPics3 (The Ending) (www.somewhere.net).jpg I am wanting to remove contents of the second parenthesis, i.e. "(www.somewhere.net)". So the files would end up like: 001 - GreatPics1 (The Opening) .jpg 002 - GreatPics2 (The Closing) .jpg 003 - GreatPics3 (The Ending) .jpg This is what I have so far. If I use this to test all is well for f in * do echo $f |sed 's:(www.somewhere.net)::' done However when I incorporate the mv command all isn't well. for f in * do chg=echo $f |sed 's:(www.somewhere.net)::' mv $f $chg done I get: bash: 001: command not found mv: target `(www.somewhere.net).jpg' is not a directory bash: 002: command not found mv: target `(www.somewhere.net).jpg' is not a directory bash: 003: command not found mv: target `(www.somewhere.net).jpg' is not a directory What am I doing wrong? Thankyou all in advance. Or use rename: rename \(www.www.somewhere.net\).jpg .jpg *.jpg I think this is fastest and clearest. --- End Message ---
Re: Bash prints syntax error when command in $(...) contains case-esac
Juergen Gohlke schrieb: Configuration Information [Automatically generated, do not change]: Machine: i686 OS: cygwin Compiler: gcc Compilation CFLAGS: -DPROGRAM='bash.exe' -DCONF_HOSTTYPE='i686' -DCONF_OSTYPE='cygwin' -DCONF_MACHTYPE='i686-pc-cygwin' -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -DRECYCLES_PIDS -I. -I/home/eblake/bash-3.2.9-11/src/bash-3.2 -I/home/eblake/bash-3.2.9-11/src/bash-3.2/include -I/home/eblake/bash-3.2.9-11/src/bash-3.2/lib -O2 -pipe uname output: CYGWIN_NT-5.0 JONA 1.5.24(0.156/4/2) 2007-01-31 10:57 i686 Cygwin Machine Type: i686-pc-cygwin Bash Version: 3.2 Patch Level: 9 Release Status: release Description: If a command in $(...) contains a case-esac construction, the bash prints a syntax error instead of executing the code: bash: syntax error near unexpected token `;;' Repeat-By: A simple example is: x=$(a=4; case $a in 3) echo a=3;; 4) echo a=4;; esac) (typed in an interactive shell or being part of a shell script). The same error has been seen on Windows Vista, Windows XP and Windows2000. The same error has been seen with an earlier version of bash, i.e. 2.05b.0(8)-release If $(...) is replaced by `...`, it works. The problem is caused by the semi-parenthesized case labels 3) and 4). Bash matches the first unpaired right paren (after the 3) with the last unpaired left paren (in $( ). Using (3) and (4) instead makes the example work. Unpaired parens are hideous anyway, IMHO. Regards, Bernd -- Bernd Eggink [EMAIL PROTECTED] http://sudrala.de
Bash prints syntax error when command in $(...) contains case-esac
Configuration Information [Automatically generated, do not change]: Machine: i686 OS: cygwin Compiler: gcc Compilation CFLAGS: -DPROGRAM='bash.exe' -DCONF_HOSTTYPE='i686' -DCONF_OSTYPE='cygwin' -DCONF_MACHTYPE='i686-pc-cygwin' -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -DRECYCLES_PIDS -I. -I/home/eblake/bash-3.2.9-11/src/bash-3.2 -I/home/eblake/bash-3.2.9-11/src/bash-3.2/include -I/home/eblake/bash-3.2.9-11/src/bash-3.2/lib -O2 -pipe uname output: CYGWIN_NT-5.0 JONA 1.5.24(0.156/4/2) 2007-01-31 10:57 i686 Cygwin Machine Type: i686-pc-cygwin Bash Version: 3.2 Patch Level: 9 Release Status: release Description: If a command in $(...) contains a case-esac construction, the bash prints a syntax error instead of executing the code: bash: syntax error near unexpected token `;;' Repeat-By: A simple example is: x=$(a=4; case $a in 3) echo a=3;; 4) echo a=4;; esac) (typed in an interactive shell or being part of a shell script). The same error has been seen on Windows Vista, Windows XP and Windows2000. The same error has been seen with an earlier version of bash, i.e. 2.05b.0(8)-release If $(...) is replaced by `...`, it works.
