[bash 3.1.5] sh -c "echo -n ok" broken

[Jeff Chua]

GNU bash, version 3.1.5(1)-release

sh -c "echo -n ok" returns "-n ok".

This breaks a lot of scripts ... startup scripts in /etc/rc.d and many 
packages like glibc "make check" that use "sh" instead of "bash" with "-n" 
option.


How can I make sh -c "echo -n ok" returns "ok" instead "-n ok"?

I've tried compiling with --disable-strict-posix-default but that doesn't 
work.



Thanks,
Jeff


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Re: [bash 3.1.5] sh -c "echo -n ok" broken

[Mike Frysinger]

On Wednesday 18 January 2006 18:34, Jeff Chua wrote:
> GNU bash, version 3.1.5(1)-release
>
> sh -c "echo -n ok" returns "-n ok".

works correctly for me:
[EMAIL PROTECTED] 0 ~ $ sh -c "echo -n ok" 
[EMAIL PROTECTED] 0 ~ $ 
-mike


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Re: [bash 3.1.5] sh -c "echo -n ok" broken

[Chet Ramey]

Jeff Chua wrote:
> 
> GNU bash, version 3.1.5(1)-release
> 
> sh -c "echo -n ok" returns "-n ok".
> 
> This breaks a lot of scripts ... startup scripts in /etc/rc.d and many
> packages like glibc "make check" that use "sh" instead of "bash" with
> "-n" option.
> 
> How can I make sh -c "echo -n ok" returns "ok" instead "-n ok"?
> 
> I've tried compiling with --disable-strict-posix-default but that
> doesn't work.

It doesn't behave that way by default:

z3.local(1)$ ./sh --version
GNU bash, version 3.1.5(2)-release (powerpc-apple-darwin8.3.0)
Copyright (C) 2005 Free Software Foundation, Inc.
z3.local(1)$ ./sh -c 'echo -n ok'
okz3.local(1)$

Somehow you've enabled the xpg_echo option, either by configuring
with --enable-xpg-echo-default or running `shopt -s xpg_echo'
somewhere.  I suspect the former.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
( ``Discere est Dolere'' -- chet )
Live Strong.
Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://cnswww.cns.cwru.edu/~chet/


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Re: [bash 3.1.5] sh -c "echo -n ok" broken

[Jeff Chua]

On Wed, 18 Jan 2006, Chet Ramey wrote:


Somehow you've enabled the xpg_echo option, either by configuring
with --enable-xpg-echo-default or running `shopt -s xpg_echo'
somewhere.  I suspect the former.


Yes, I did "--enable-xpg-echo-default" as I need echo "ok\c" to work.

The older bash-3.00.15(3) works with "--enable-xpg-echo-default".


So, it is possible to have both the following working in "sh" and "bash"

echo -n "ok"
echo "ok\c"

Thanks,
Jeff.




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Re: [bash 3.1.5] sh -c "echo -n ok" broken

[Chris F.A. Johnson]

On Thu, 19 Jan 2006, Jeff Chua wrote:


On Wed, 18 Jan 2006, Chet Ramey wrote:


Somehow you've enabled the xpg_echo option, either by configuring
with --enable-xpg-echo-default or running `shopt -s xpg_echo'
somewhere.  I suspect the former.


Yes, I did "--enable-xpg-echo-default" as I need echo "ok\c" to work.

The older bash-3.00.15(3) works with "--enable-xpg-echo-default".


So, it is possible to have both the following working in "sh" and "bash"

echo -n "ok"
echo "ok\c"


printf "%s" "ok"

--
   Chris F.A. Johnson  
   ===
   Author:
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)


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Re: [bash 3.1.5] sh -c "echo -n ok" broken

[Chet Ramey]

> So, it is possible to have both the following working in "sh" and "bash"
> 
>   echo -n "ok"
>   echo "ok\c"

No.  In posix mode, they are fundamentally incompatible.  The combination of
posix mode and xpg-echo cause bash to be strictly posix compliant and disable
any option processing.

This is item `c' in the New Features section of NEWS.

Chet

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
( ``Discere est Dolere'' -- chet )
Live Strong.
Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://tiswww.tis.case.edu/~chet/


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