subject:"Closing $ajax\\\-form\\$\\$"

Re: Closing $ajax-form()

2009-01-27 Thread Pyrite


I can't get $ajax-submit() to work, only $form-end('Submit').

What's the difference between the two?

On Jan 26, 7:59 am, Graham Weldon gra...@grahamweldon.com wrote:
 $ajax-submit() creates an ajax submit element.
 $form-end('something') creates a submit button, and ends the form.

 $ajax-form() starts a form.
 Your usage will depends very much on your implementation, and requirements.

 The simple reason for there not being an $ajax-formEnd() is because its
 super easy to do: $form-end().
 Both output /form.

 here are some options to illustrate usage:

 $form-create();
   $form-inputs();
 $form-end('submit');

 $ajax-form();
   $form-inputs();
 $form-end('submit');

 $ajax-form();
   $form-inputs();
   $ajax-submit();
 $form-end();

 On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com
 wrote:



  So what is the point/usage of $ajax-submit() then if it does not
  actually submit the form created with $ajax-form() ?

  On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote:
  When u use the ajax-form, the only difference with a normal form is
  the first line.

  Normal Form:

  $form-create (...)
    $form-input ()
    $form-input ()
  $form-end ('Send')

  Ajax Form:

  $ajax-form (...)
    $form-input ()
    $form-input ()
  $form-end ('Send')

  On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote:

   How do you put the close tag in a form created by $ajax-form() ?? Why
   is there not an $ajax-formEnd() similar to the FormHelper's
 $form-end
   () ?

   Also, when I create a form with $ajax-form(), and I add a submit with
   $ajax-submit(), it does not submit the form. A usage example would be
   great. I can only get it to submit the form if I use $form-end
   ('Submit') instead of $ajax-submit().- Hide quoted text -

  - Show quoted text -- Hide quoted text -

 - Show quoted text -
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Re: Closing $ajax-form()

2009-01-27 Thread Graham Weldon




$ajax-submit() will create a submit button.
However, it will not end your form.
You need to also end your form with $form-end().


$ajax-submit() will work, as indicated previously:
 $ajax-form();
   $form-inputs();
   $ajax-submit();
 $form-end();

Cheers,
Graham


On Tue, 27 Jan 2009 06:21:45 -0800 (PST), Pyrite thelette...@gmail.com
wrote:
 I can't get $ajax-submit() to work, only $form-end('Submit').
 
 What's the difference between the two?
 
 On Jan 26, 7:59 am, Graham Weldon gra...@grahamweldon.com wrote:
 $ajax-submit() creates an ajax submit element.
 $form-end('something') creates a submit button, and ends the form.

 $ajax-form() starts a form.
 Your usage will depends very much on your implementation, and
 requirements.

 The simple reason for there not being an $ajax-formEnd() is because its
 super easy to do: $form-end().
 Both output /form.

 here are some options to illustrate usage:

 $form-create();
   $form-inputs();
 $form-end('submit');

 $ajax-form();
   $form-inputs();
 $form-end('submit');

 $ajax-form();
   $form-inputs();
   $ajax-submit();
 $form-end();

 On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com
 wrote:



  So what is the point/usage of $ajax-submit() then if it does not
  actually submit the form created with $ajax-form() ?

  On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote:
  When u use the ajax-form, the only difference with a normal form is
  the first line.

  Normal Form:

  $form-create (...)
    $form-input ()
    $form-input ()
  $form-end ('Send')

  Ajax Form:

  $ajax-form (...)
    $form-input ()
    $form-input ()
  $form-end ('Send')

  On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote:

   How do you put the close tag in a form created by $ajax-form() ??
   Why
   is there not an $ajax-formEnd() similar to the FormHelper's
 $form-end
   () ?

   Also, when I create a form with $ajax-form(), and I add a submit
   with
   $ajax-submit(), it does not submit the form. A usage example would
   be
   great. I can only get it to submit the form if I use $form-end
   ('Submit') instead of $ajax-submit().- Hide quoted text -

  - Show quoted text -- Hide quoted text -

 - Show quoted text -
 
-- 
Cheers,

Graham Weldon
w. http://grahamweldon.com
e. gra...@grahamweldon.com
p. +61 407 017 293

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Re: Closing $ajax-form()

2009-01-26 Thread Pyrite


So what is the point/usage of $ajax-submit() then if it does not
actually submit the form created with $ajax-form() ?

On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote:
 When u use the ajax-form, the only difference with a normal form is
 the first line.

 Normal Form:

 $form-create (...)
   $form-input ()
   $form-input ()
 $form-end ('Send')

 Ajax Form:

 $ajax-form (...)
   $form-input ()
   $form-input ()
 $form-end ('Send')

 On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote:



  How do you put the close tag in a form created by $ajax-form() ?? Why
  is there not an $ajax-formEnd() similar to the FormHelper's $form-end
  () ?

  Also, when I create a form with $ajax-form(), and I add a submit with
  $ajax-submit(), it does not submit the form. A usage example would be
  great. I can only get it to submit the form if I use $form-end
  ('Submit') instead of $ajax-submit().- Hide quoted text -

 - Show quoted text -
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Re: Closing $ajax-form()

2009-01-26 Thread Graham Weldon




$ajax-submit() creates an ajax submit element.
$form-end('something') creates a submit button, and ends the form.

$ajax-form() starts a form.
Your usage will depends very much on your implementation, and requirements.

The simple reason for there not being an $ajax-formEnd() is because its
super easy to do: $form-end().
Both output /form.

here are some options to illustrate usage:


$form-create();
  $form-inputs();
$form-end('submit');

$ajax-form();
  $form-inputs();
$form-end('submit');

$ajax-form();
  $form-inputs();
  $ajax-submit();
$form-end();



On Mon, 26 Jan 2009 05:55:02 -0800 (PST), Pyrite thelette...@gmail.com
wrote:
 So what is the point/usage of $ajax-submit() then if it does not
 actually submit the form created with $ajax-form() ?
 
 On Jan 23, 8:05 am, Mono sirmonit...@gmail.com wrote:
 When u use the ajax-form, the only difference with a normal form is
 the first line.

 Normal Form:

 $form-create (...)
   $form-input ()
   $form-input ()
 $form-end ('Send')

 Ajax Form:

 $ajax-form (...)
   $form-input ()
   $form-input ()
 $form-end ('Send')

 On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote:



  How do you put the close tag in a form created by $ajax-form() ?? Why
  is there not an $ajax-formEnd() similar to the FormHelper's
$form-end
  () ?

  Also, when I create a form with $ajax-form(), and I add a submit with
  $ajax-submit(), it does not submit the form. A usage example would be
  great. I can only get it to submit the form if I use $form-end
  ('Submit') instead of $ajax-submit().- Hide quoted text -

 - Show quoted text -
 

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Re: Closing $ajax-form()

2009-01-23 Thread Mono


When u use the ajax-form, the only difference with a normal form is
the first line.

Normal Form:

$form-create (...)
  $form-input ()
  $form-input ()
$form-end ('Send')

Ajax Form:

$ajax-form (...)
  $form-input ()
  $form-input ()
$form-end ('Send')








On 22 Jan., 22:47, Pyrite thelette...@gmail.com wrote:
 How do you put the close tag in a form created by $ajax-form() ?? Why
 is there not an $ajax-formEnd() similar to the FormHelper's $form-end
 () ?

 Also, when I create a form with $ajax-form(), and I add a submit with
 $ajax-submit(), it does not submit the form. A usage example would be
 great. I can only get it to submit the form if I use $form-end
 ('Submit') instead of $ajax-submit().

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Closing $ajax-form()

2009-01-22 Thread Pyrite


How do you put the close tag in a form created by $ajax-form() ?? Why
is there not an $ajax-formEnd() similar to the FormHelper's $form-end
() ?

Also, when I create a form with $ajax-form(), and I add a submit with
$ajax-submit(), it does not submit the form. A usage example would be
great. I can only get it to submit the form if I use $form-end
('Submit') instead of $ajax-submit().
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CakePHP group.
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Re: Closing $ajax-form()

2009-01-22 Thread Yusuf Widiyatmono

i use $form-end();

and it does submit trough ajax updater successfully.


see the code which is generated by ajax-form();
you will figure out that it just a normal new Ajax.Updater().


sometimes i meet my limitation when use ajax on cake, 
so i just write normal html and javascript on the view layer.




From: Pyrite thelette...@gmail.com
To: CakePHP cake-php@googlegroups.com
Sent: Friday, January 23, 2009 6:47:09 AM
Subject: Closing $ajax-form()


How do you put the close tag in a form created by $ajax-form() ?? Why
is there not an $ajax-formEnd() similar to the FormHelper's $form-end
() ?

Also, when I create a form with $ajax-form(), and I add a submit with
$ajax-submit(), it does not submit the form. A usage example would be
great. I can only get it to submit the form if I use $form-end
('Submit') instead of $ajax-submit().


  
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Re: Closing $ajax-form()

Re: Closing $ajax-form()

Re: Closing $ajax-form()

Re: Closing $ajax-form()

Re: Closing $ajax-form()

Closing $ajax-form()

Re: Closing $ajax-form()

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