Re: Best Practice: Views, renderElement
Put your element code in app/view/elements
and you can display them with:
echo $this-renderElement(element_name);
On Nov 21, 8:52 am, releod [EMAIL PROTECTED] wrote:
Hello, I am wondering if there is a better approach to this built into
CakePHP 1.2
Basically I have a few views, admin_create, admin_update,
admin_destroy, all using the same code for the form.
I have created another view file called _admin_form.ctp
Right now, for example, I write:
$this-renderElement('../user/_admin_form');
inside of my admin_create.ctp, is there anyway to
render('_admin_form'); without needing to jump out of the current
directory? (_admin_form is in the users directory along with the other
views).
Thanks!
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Re: Best Practice: Views, renderElement
From my understanding, if you have a form (or any other chunk of html)
that is used by several views, then it clearly qualifies as an
element. Sure, it's a private element (only used by views in /user),
but still an element.
You could always create subfolders under the elements folder, so you'd
have $this-renderElement('user/admin_form'); to render app/views/
elements/user/admin_form.ctp.
If that seems odd to you, try creating an 'elements' subfolder under
app/views/user/, then registering app/views/user as a view path (in
bootstrap.php), so that View::renderElement() will look there too.
That feels a bit hacky, but should work.
On Nov 21, 8:52 am, releod [EMAIL PROTECTED] wrote:
Hello, I am wondering if there is a better approach to this built into
CakePHP 1.2
Basically I have a few views, admin_create, admin_update,
admin_destroy, all using the same code for the form.
I have created another view file called _admin_form.ctp
Right now, for example, I write:
$this-renderElement('../user/_admin_form');
inside of my admin_create.ctp, is there anyway to
render('_admin_form'); without needing to jump out of the current
directory? (_admin_form is in the users directory along with the other
views).
Thanks!
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Re: Best Practice: Views, renderElement
Cool, thanks - makes sense.
On Nov 21, 4:52 am, grigri [EMAIL PROTECTED] wrote:
From my understanding, if you have a form (or any other chunk of html)
that is used by several views, then it clearly qualifies as an
element. Sure, it's a private element (only used by views in /user),
but still an element.
You could always create subfolders under the elements folder, so you'd
have $this-renderElement('user/admin_form'); to render app/views/
elements/user/admin_form.ctp.
If that seems odd to you, try creating an 'elements' subfolder under
app/views/user/, then registering app/views/user as a view path (in
bootstrap.php), so that View::renderElement() will look there too.
That feels a bit hacky, but should work.
On Nov 21, 8:52 am, releod [EMAIL PROTECTED] wrote:
Hello, I am wondering if there is a better approach to this built into
CakePHP 1.2
Basically I have a few views, admin_create, admin_update,
admin_destroy, all using the same code for the form.
I have created another view file called _admin_form.ctp
Right now, for example, I write:
$this-renderElement('../user/_admin_form');
inside of my admin_create.ctp, is there anyway to
render('_admin_form'); without needing to jump out of the current
directory? (_admin_form is in the users directory along with the other
views).
Thanks!
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PHP group.
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Re: Best Practice: Views, renderElement
Another solution extend basic view class.
?php
class ExView extends View
{
function renderPartial($name, $params = array(), $loadHelpers =
false) {
if ((strpos($name, '\\')===false) (strpos($name,
'/')===false)) {
$name = '..' . DS . Inflector::underscore($this-name)
. DS .
$name;
}
return $this-renderElement($name, $params, $loadHelpers);
}
}
?
And set this class as default view class
?php
class AppController extends Controller {
var $helpers = array('Debug','Javascript','Html','Jquery');
function beforeRender() {
$this-view='Ex';
return true;
}
}
?
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Re: Best Practice: Views, renderElement
Where is the best place to keep files that extend the CORE CAKE
Framework?
On Nov 21, 10:30 am, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Another solution extend basic view class.
?php
class ExView extends View
{
function renderPartial($name, $params = array(), $loadHelpers =
false) {
if ((strpos($name, '\\')===false) (strpos($name,
'/')===false)) {
$name = '..' . DS .
Inflector::underscore($this-name) . DS .
$name;
}
return $this-renderElement($name, $params, $loadHelpers);
}
}
?
And set this class as default view class
?php
class AppController extends Controller {
var $helpers = array('Debug','Javascript','Html','Jquery');
function beforeRender() {
$this-view='Ex';
return true;
}
}
?
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Re: Best Practice: Views, renderElement
In place where thay should be. For view class extensisions correct place is /app/views folder BTW: @grigri Your proposiiton need aditional manual work. We need to describe each subview folder in bootstrap or create aditional code that will take time. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
