Re: How to write one single query for fetching data from two tables

2009-07-27 Thread Vijay Kumbhar
Yes , RWS - Bharat Maheriya  is right.

If you are writing queries for joins in the fabulous framework like cakephp
then what is the need to us the framwork.
Cakephp has a good feature of associations so please use that to join the
tables.
You have to write custom queries only few times & it is negligible.

So my suggestion is dont break the rules of the framework.

On Mon, Jul 27, 2009 at 11:33 AM, RWS - Bharat Maheriya <
rws.bha...@gmail.com> wrote:

> Hello
>
> you can define model association between agent and device and perform find
> operation  with condition agents.verified=1only..CakePHP association perfom
> internal joining and give you expected result. you can try out with this...
>
> Thanks
>
>
>
> On Wed, Jul 22, 2009 at 7:17 PM, mona  wrote:
>
>>
>> How to write the folowing query in cakephp
>>
>>  $sql = "select
>> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
>> devices,agents where devices.uid = agents.uid and agents.verified=1
>> limit 100";
>>
>> Followin is my controller file
>>
>> class AgentsController extends AppController {
>>var $name = 'Agents';
>>var $helpers =
>> array('Html','Form','Xml','Text','Javascript','Ajax');
>>var $uses = array( 'Agent','Device');
>>var $components = array('RequestHandler');
>>
>>
>>function admin_exportDevice(){
>>$this->_adminOnly();
>>$export = trim($this->data['deviceExport']['export']);
>>if($export=='Full'){
>>   $sql = "select
>> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
>> devices,agents where devices.uid =   agents.uid and agents.verified=1
>> limit 100";
>>  $qry = mysql_query($sql);
>>$this->set('qry', $qry);
>>$this->set('filename', 'Full'.date("Ymd").'.xml');
>>$this->layout='ajax';
>>
>>$sql1 = "Update devices set export=1 where export=0";
>>$query = mysql_query($sql1);
>>}
>> else{
>>   $sql = "select
>> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
>> devices,agents where devices.uid = agents.uid and agents.verified=1
>> and devices.export=0 limit 2";
>>$qry = mysql_query($sql);
>>$this->set('qry', $qry);
>>$this->set('filename', 'Incremental'.date("Ymd").'.xml');
>>$this->layout='ajax';
>>$sql1 = "Update devices set export=1 where export=0";
>>$query = mysql_query($sql1);
>>
>>  }
>>}
>> }
>>
>>
>
> >
>


-- 
Thanks & Regards,
Vijayk.
Co-founder (www.weboniselab.com)

"You Bring the Dreams, We'll Bring the Means"

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Re: How to write one single query for fetching data from two tables

2009-07-27 Thread RWS - Bharat Maheriya
Hello

you can define model association between agent and device and perform find
operation  with condition agents.verified=1only..CakePHP association perfom
internal joining and give you expected result. you can try out with this...

Thanks


On Wed, Jul 22, 2009 at 7:17 PM, mona  wrote:

>
> How to write the folowing query in cakephp
>
>  $sql = "select
> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
> devices,agents where devices.uid = agents.uid and agents.verified=1
> limit 100";
>
> Followin is my controller file
>
> class AgentsController extends AppController {
>var $name = 'Agents';
>var $helpers =
> array('Html','Form','Xml','Text','Javascript','Ajax');
>var $uses = array( 'Agent','Device');
>var $components = array('RequestHandler');
>
>
>function admin_exportDevice(){
>$this->_adminOnly();
>$export = trim($this->data['deviceExport']['export']);
>if($export=='Full'){
>   $sql = "select
> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
> devices,agents where devices.uid =   agents.uid and agents.verified=1
> limit 100";
>  $qry = mysql_query($sql);
>$this->set('qry', $qry);
>$this->set('filename', 'Full'.date("Ymd").'.xml');
>$this->layout='ajax';
>
>$sql1 = "Update devices set export=1 where export=0";
>$query = mysql_query($sql1);
>}
> else{
>   $sql = "select
> devices.uid,devices.agent,devices.capabilities,devices.localcaps from
> devices,agents where devices.uid = agents.uid and agents.verified=1
> and devices.export=0 limit 2";
>$qry = mysql_query($sql);
>$this->set('qry', $qry);
>$this->set('filename', 'Incremental'.date("Ymd").'.xml');
>$this->layout='ajax';
>$sql1 = "Update devices set export=1 where export=0";
>$query = mysql_query($sql1);
>
>  }
>}
> }
> >
>

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