Re: generateList deprecated ... how to find a list with conditions?

2008-01-14 Thread francky06l

http://groups.google.com/group/cake-php/browse_thread/thread/3a03f75d1c0fc378

On Jan 15, 3:03 am, jason m <[EMAIL PROTECTED]> wrote:
> How about if you want a list with two fields like Post.id =>
> Post.title?
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Re: generateList deprecated ... how to find a list with conditions?

2008-01-14 Thread jason m

How about if you want a list with two fields like Post.id =>
Post.title?

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Re: generateList deprecated ... how to find a list with conditions?

2008-01-11 Thread [EMAIL PROTECTED]

$this->Post->find('list', array ('conditions' => array("Post.title" =>
"<> This is a post"') );
This will find the ones that are not equal.
$this->Post->find('list', array ('conditions' => array("Post.title" =>
"This is a post"') , 'order'=>array('Post.title'=>'ASC') );
This will find all posts that Post.title="this is a post" and will
order ascendant by Post.title


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Re: generateList deprecated ... how to find a list with conditions?

2008-01-10 Thread Baz
find('list', array ('conditions' => array() );

On Jan 10, 2008 11:42 AM, aranworld <[EMAIL PROTECTED]> wrote:

>
> In the latest 1.2 Beta, I am noticing that generateList is deprecated
> and to be replaced with find("list").
>
> But how am I supposed to add a condition to the find if the first
> argument is the string "list"?
>
> Can anyone help me figure out how to replicate a generateList with
> conditions using the new proper syntax?
> >
>

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generateList deprecated ... how to find a list with conditions?

2008-01-10 Thread aranworld

In the latest 1.2 Beta, I am noticing that generateList is deprecated
and to be replaced with find("list").

But how am I supposed to add a condition to the find if the first
argument is the string "list"?

Can anyone help me figure out how to replicate a generateList with
conditions using the new proper syntax?
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