Re: Undefined reference to "S_ISDIR" and "S_ISREG" when compiling with "-betterC"
On Monday, 10 January 2022 at 21:17:22 UTC, Adam D Ruppe wrote: It's not a system call, it just a bitflag tester. I wasn't talking about the flag actually but for the "stat" system call
Re: A slice consisting of non-consecutive elements of an array?
On Thursday, 13 January 2022 at 20:32:40 UTC, Stanislav Blinov wrote: On Thursday, 13 January 2022 at 19:52:27 UTC, forkit wrote: Any idea on how I can get a ptr (without hardcoding C style) e.g. something like this: immutable(string)*[] pointers = strings.filter!(x => x == "one").to!pointers.array; ```d import std.stdio : writeln; import std.algorithm : filter, map, each; import std.range : array; void main() @safe { immutable strings = ["one", "one", "two", "one", "two", "one", "one", "two"]; immutable(string)*[] pointers = strings.filter!(x => x == "one").map!((ref x) @trusted => ).array; pointers.each!(p => writeln(p - [0])); } ``` just perfect! thanks.
Re: A slice consisting of non-consecutive elements of an array?
On Thursday, 13 January 2022 at 19:52:27 UTC, forkit wrote: Any idea on how I can get a ptr (without hardcoding C style) e.g. something like this: immutable(string)*[] pointers = strings.filter!(x => x == "one").to!pointers.array; ```d import std.stdio : writeln; import std.algorithm : filter, map, each; import std.range : array; void main() @safe { immutable strings = ["one", "one", "two", "one", "two", "one", "one", "two"]; immutable(string)*[] pointers = strings.filter!(x => x == "one").map!((ref x) @trusted => ).array; pointers.each!(p => writeln(p - [0])); } ```
Re: A slice consisting of non-consecutive elements of an array?
On Wednesday, 12 January 2022 at 06:16:49 UTC, vit wrote: Yes std.algorithm : filter. ```d import std.stdio : writeln; import std.algorithm : filter; void main()@safe{ auto a = ["one", "one", "two", "one", "two", "one", "one", "two"]; writeln(a); writeln(a.filter!(x => x == "one")); } ``` Any idea on how I can get a ptr (without hardcoding C style) e.g. something like this: immutable(string)*[] pointers = strings.filter!(x => x == "one").to!pointers.array;