Re: Why do I get stack overflow?
Ary Borenszweig: > Thanks. Later in my head I instantiated the template and noticed the > problem. In time I have created similar problems in my code 2-3 times, missing a "static" before some "if". Can't the compiler help spot such bugs? If the variables a dynamic if works on are constants (expecially if they are types) the compiler may give a warning... Bye, bearophile
Re: Why do I get stack overflow?
Moritz Warning escribió:
On Sun, 24 May 2009 20:49:53 -0300, Ary Borenszweig wrote:
When I compile this code I get "stack overflow" printed in the console.
Anyone know why?
---
int fact(int X)() {
if(X == 0) {
return 1;
} else {
int temp = fact!(X - 1)();
return X * temp;
}
}
const someVar = fact!(0)();
---
Because you generate fact!(-1)(), fact!(-2)() and so on at compile time.
You recursive template doesn't terminate.
Thanks. Later in my head I instantiated the template and noticed the
problem.
Re: Why do I get stack overflow?
On Sun, 24 May 2009 20:49:53 -0300, Ary Borenszweig wrote:
> When I compile this code I get "stack overflow" printed in the console.
> Anyone know why?
>
> ---
> int fact(int X)() {
> if(X == 0) {
> return 1;
> } else {
> int temp = fact!(X - 1)();
> return X * temp;
> }
> }
>
> const someVar = fact!(0)();
> ---
Because you generate fact!(-1)(), fact!(-2)() and so on at compile time.
You recursive template doesn't terminate.
Re: Why do I get stack overflow?
Ary Borenszweig wrote:
When I compile this code I get "stack overflow" printed in the console.
Anyone know why?
---
int fact(int X)() {
if(X == 0) {
return 1;
} else {
int temp = fact!(X - 1)();
return X * temp;
}
}
const someVar = fact!(0)();
---
Like Moritz said. You need to use "static if" there rather than "if".
Why do I get stack overflow?
When I compile this code I get "stack overflow" printed in the console.
Anyone know why?
---
int fact(int X)() {
if(X == 0) {
return 1;
} else {
int temp = fact!(X - 1)();
return X * temp;
}
}
const someVar = fact!(0)();
---
