Re: something I really don't know in using manage.py shell

[oggie rob]

Yes. "filter" returns a set (hence the [] around "",
indicating a collection). If you are using a pk, where you can
guarantee a single returned value, use "get":
>>> p = Profile.objects.get(id=1)
>>> p.department

 -rob

On Aug 1, 10:35 pm, james_027 <[EMAIL PROTECTED]> wrote:
> hi,
>
> i am trying to use the manage.py shell, for fast testing of what I
> would like to do.
>
> I have a model like this
>
> class Function(models.Model):
> """Functions that KSK Employee account could use"""
>
> name = models.CharField(maxlength=40)
> url = models.CharField(maxlength=40, default='/')
> method = models.CharField(maxlength=40, default='index')
>
> class Profile(models.Model):
> """KSK Employee accounts to use this application"""
>
> user = models.ForeignKey(User, unique=True)
> department = models.CharField(maxlength=3,
> choices=DEPARTMENT_LIST)
> level = models.CharField(maxlength=2, choices=LEVEL_LIST)
> functions = models.ManyToManyField(Function, blank=True)
>
> when I do in the shell
>
> >>>p = Profile.objects.filter(id=1)
> >>>p
>
> []
> but when I did this>>>p.department
>
> it say
> AttributeError: '_QuerySet' object has no attribute 'level'
>
> is there anything I should know?
>
> THanks
> james


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Re: something I really don't know in using manage.py shell

[Lucky B]

You should be doing
>>> p = Profile.objects.get(id=1)#or .get(1) or one of the many other 
>>> posibilities

filter returns a list of the results, in the case of id=# it probably
returns only one, but it's still a list of one member.

So in your case it would work if you did this:
>>>p= Profile.objects.filter(id=1)
>>>print p[0]

On Aug 2, 1:35 am, james_027 <[EMAIL PROTECTED]> wrote:
> hi,
>
> i am trying to use the manage.py shell, for fast testing of what I
> would like to do.
>
> I have a model like this
>
> class Function(models.Model):
> """Functions that KSK Employee account could use"""
>
> name = models.CharField(maxlength=40)
> url = models.CharField(maxlength=40, default='/')
> method = models.CharField(maxlength=40, default='index')
>
> class Profile(models.Model):
> """KSK Employee accounts to use this application"""
>
> user = models.ForeignKey(User, unique=True)
> department = models.CharField(maxlength=3,
> choices=DEPARTMENT_LIST)
> level = models.CharField(maxlength=2, choices=LEVEL_LIST)
> functions = models.ManyToManyField(Function, blank=True)
>
> when I do in the shell
>
> >>>p = Profile.objects.filter(id=1)
> >>>p
>
> []
> but when I did this>>>p.department
>
> it say
> AttributeError: '_QuerySet' object has no attribute 'level'
>
> is there anything I should know?
>
> THanks
> james


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Re: something I really don't know in using manage.py shell

[johan de taeye]

I suspect you get this error because "level" is a reserved keyword in
many databases.
Try renaming the field.

Johan


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something I really don't know in using manage.py shell

[james_027]

hi,

i am trying to use the manage.py shell, for fast testing of what I
would like to do.

I have a model like this

class Function(models.Model):
"""Functions that KSK Employee account could use"""

name = models.CharField(maxlength=40)
url = models.CharField(maxlength=40, default='/')
method = models.CharField(maxlength=40, default='index')

class Profile(models.Model):
"""KSK Employee accounts to use this application"""

user = models.ForeignKey(User, unique=True)
department = models.CharField(maxlength=3,
choices=DEPARTMENT_LIST)
level = models.CharField(maxlength=2, choices=LEVEL_LIST)
functions = models.ManyToManyField(Function, blank=True)

when I do in the shell

>>>p = Profile.objects.filter(id=1)
>>>p
[]
but when I did this
>>>p.department
it say
AttributeError: '_QuerySet' object has no attribute 'level'

is there anything I should know?

THanks
james


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