Re: date question
Charles K. Clarkson wrote:
Lori <[EMAIL PROTECTED]> wrote:
: This is a postgresql question , slam me if you must, but
: this is the only list where I get a fast response and I
: know many of you use postgresql
:
: I have a int field called when_month and I want to use
: it to get the full month name something like :
: update mytable set myfield = date_part(month,'1/5/2004');
: the problem is date part returns 5 not May
:
: If I wanted to do this in a program I could easily
: do it with an array ,but cant find quick way to do in
: postgresql ?
:
: I have looked it up on the postgresql site and on google
: but cant find a simple function that will do the trick
I think you want the "to_char" or the "to_timestamp"
function. (Read the note.)
http://www.postgresql.org/docs/7/interactive/functions2976.htm
HTH,
Charles K. Clarkson
thanks charles, I have been playing with those 2 functions for the last
hour or so, i
this comes close to what I want
update mytable set myfield=to_char(current_timestamp,'MON');
the result is myfield is set to OCT which is what I want but when I try
to use a variable
update mytable set myfield=to_char('20040505','MON');
get error:
update mytable set myfield=to_date(when_month,'MON');
update mytable set myfield=to_char('05','MON');
as well as
update mytable set full_month= to_date('01/'05'/2004','DDMON');
all get errors
back to the drawing board
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RE: date question
Lori <[EMAIL PROTECTED]> wrote: : This is a postgresql question , slam me if you must, but : this is the only list where I get a fast response and I : know many of you use postgresql : : I have a int field called when_month and I want to use : it to get the full month name something like : : update mytable set myfield = date_part(month,'1/5/2004'); : the problem is date part returns 5 not May : : If I wanted to do this in a program I could easily : do it with an array ,but cant find quick way to do in : postgresql ? : : I have looked it up on the postgresql site and on google : but cant find a simple function that will do the trick I think you want the "to_char" or the "to_timestamp" function. (Read the note.) http://www.postgresql.org/docs/7/interactive/functions2976.htm HTH, Charles K. Clarkson -- Mobile Homes Specialist 254 968-8328 ___ Perl-Win32-Users mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: date question
Lori, I'm not that familar with Postgresql, however you should check out the online documentation on SQL Functions and roll your own. Here's the link to the page. http://www.postgresql.org/docs/aw_pgsql_book/node164.html Several of the examples appear to be close to what I think you're looking for in a function. Cheers, Carter. > -Original Message- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On > Behalf Of Lori > Sent: Tuesday, October 12, 2004 2:29 PM > To: [EMAIL PROTECTED] > Subject: date question > > > This is a postgresql question , slam me if you must, but this is the > only list where I get a > fast response and I know many of you use postgresql > > I have a int field called when_month and I want to use it to get the > full month name > something like : > update mytable set myfield = date_part(month,'1/5/2004'); > the problem is date part returns 5 not May > > If I wanted to do this in a program I could easily do it with an > array ,but cant find quick way to do in postgresql ? > > I have looked it up on the postgresql site and on google but > cant find a > simple function that will do the trick > > > ___ > Perl-Win32-Users mailing list > [EMAIL PROTECTED] > To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs > ___ Perl-Win32-Users mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Date question
I
use Date::Calc;
although there are lots of Date modules available.
paula
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of
Stephen J Martin
Sent: Wednesday, May 22, 2002 7:54 AM
To: [EMAIL PROTECTED]
Cc: Carl Jolley
Subject: Re: Date question
On Tue, 21 May 2002 22:11:53
Carl Jolley wrote:
>This is a difficult question but I'll try to answer.
>OR if you wanted to correctly wrap from December to January of the
>following year;
>
>my ($mday, $mon, $year) = (localtime(time))[3..5];
>$mon+=1;
>$year+=1900;
>my $startdate = sprintf "%02u/%02u/%u", $mon, $mday, $year;
>if(++$mon==13) {
> $mon=1;
> $year++;
>}
>my $lastdate = sprintf "%02u/%02u/%u", $mon, $mday, $year+1900;
>
>On Tue, 21 May 2002 [EMAIL PROTECTED] wrote:
>
>> I have a question about my date snippet.
It's more difficult even than that, e.g. on 31st May the code above will give 31st
June, which is invalid. In fact, on my machine today it gives "06/22/3902", so adding
1900 to the year was not necessary.
I could have a go at this, but surely it's been done before?
By the way, what should you do with short months? Always advance by 31 days or just
collapse several days to the last day of the month? Do banks/ accountants/ the law
have a strict definition of "one month from today" that works in all cases? Is it
different in the US/ UK/ Europe/ elsewhere?
---
Steve Martin
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Re: Re: Date question
I have used this little snippet for a lot of my programs. I know I'm jumping in line
here but maybe this will work for you too:
my @days = ("Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday");
my @months =
("January","February","March","April","May","June","July","August","September","October","November","December");
($sec,$min,$hr,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time);
my $year = $year + 1900;
then I just called it like this:
$days[$wday], $months[$mon] $mday, $year
Mark Bergeron
-Original Message-
From: "$Bill Luebkert"<[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Tue May 21 15:25:06 PDT 2002
Subject: Re: Date question
>[EMAIL PROTECTED] wrote:
>
>> I have a question about my date snippet.
>>
>> my ($mday, $mon, $year) = (localtime(time))[3..5];
>> my $pagedate = sprintf "%02u/%02u/%u", $mon + 1, $mday,
>> $year + 1900;
>>
>> The above will print out the date like "05/21/2002"
>>
>> How can I create the date exactically to the same day but
>> to the following month?
>>
>> Then I would have: start date "05/21/2002"
>>end date "06/21/2002"
>
>
>Maybe add 1 to $mon ???
>
>
>> Or for whatever date
>
>
>my ($mday, $mon, $year) = (localtime (time + $diff_in_secs_to_new_date))[3..5];
>
>then feed the vars to timelocal (Time::Local) to get your future epoch time.
>
>You can flip back and forth between localtime and timelocal to get
>exact days of month or month of year, etc.
>
>--
> ,-/- __ _ _ $Bill Luebkert ICQ=14439852
> (_/ / )// // DBE Collectibles Mailto:[EMAIL PROTECTED]
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>
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RE: Date question
It depends on what you mean by "following month." How do you define the following month after May 31? Is it June 30? How do you define the following month after June 30? Is it July 30? or is it July 31? February 28 -> March 28? or March 31? Do you mean last number of the month, exactly 30 days after, or the same number as the previous month? It's all possible to do, you just have to know what you mean by "following month." -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Tuesday, May 21, 2002 3:57 PM To: [EMAIL PROTECTED] Subject: Date question I have a question about my date snippet. my ($mday, $mon, $year) = (localtime(time))[3..5]; my $pagedate = sprintf "%02u/%02u/%u", $mon + 1, $mday, $year + 1900; The above will print out the date like "05/21/2002" How can I create the date exactically to the same day but to the following month? Then I would have: start date "05/21/2002" end date "06/21/2002" Or for whatever date Thanks in advance. Allan ___ Perl-Win32-Users mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs ___ Perl-Win32-Users mailing list [EMAIL PROTECTED] To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
