That worked perfectly. Thanks a lot!
On Tue, Mar 5, 2013 at 12:49 PM, ChoonSoo Park luisp...@gmail.com wrote:
Try this one.
select X.client_id, array_agg(X.color)
from (select distinct client_id, unnest(service_codes) as color
from foo) X
group by X.client_id;
On Tue, Mar 5, 2013 at 3:28 PM, Ken Tanzer ken.tan...@gmail.com wrote:
I have a field containing a set of codes in a varchar array, each tied to
a person.
client_id | integer
|
service_codes | character varying(10)[] |
I'm trying to query this info so that I can get the list (presumably in
an array) of all the values in this array, across all the records for a
client. So that if a person has two records, one with ORANGE and BLUE, and
one with BLUE and GREEN, I could end up with a list of ORANGE, BLUE and
GREEN.
I had hopes for:
SELECT client_id,array_agg(service_codes) FROM foo GROUP BY client_id;
But was rebuffed with ERROR: could not find array type for data type
character varying[]
There's probably an easy answer for this, but it's completely escaping
me. Any help appreciated. Thanks.
Ken
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--
AGENCY Software
A data system that puts you in control
100% Free Software
*http://agency-software.org/*
ken.tan...@agency-software.org
(253) 245-3801
Subscribe to the mailing
listagency-general-requ...@lists.sourceforge.net?body=subscribe
to
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follow the discussion.