Re: [PHP] INSERT problem with MySQL/PHP
Only a small little problem.. you called your sql query $sql and then in
your mysql_db_query line called it $sql_query..call them both the same name
and it should work!
HTH,Tom
- Original Message -
From: "Todd A. Jacobs" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Tuesday, June 19, 2001 12:11 AM
Subject: [PHP] INSERT problem with MySQL/PHP
> PHP: 4.0.4pl1
> MySQL: 3.23.36-1
>
> I have the following code fragment, which uses the same connection
> parameters elsewhere to *successfully* to retrieve data from a database,
> so this doesn't appear to be a permissions problem with MySQL.
>
> However, nothing happens with inserts; no rows are added at all. All I get
> is a message form mysql_error() saying "Query was empty."
>
> Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
>
> echo "";
> echo "\nDebugging output:\n";
> echo "\tSQL: $sql\n";
> echo "\tError: ", mysql_error(), "\n";
> echo "\tLast insert ID: ", mysql_insert_id(), "\n";
> echo "\tResult: $result\n";
> echo "\n";
>
> --
> Todd A. Jacobs
> CodeGnome Consulting, LTD
>
Re: [PHP] INSERT problem with MySQL/PHP
On Tue, 19 Jun 2001 08:41, Todd A. Jacobs wrote:
> PHP: 4.0.4pl1
> MySQL: 3.23.36-1
>
> I have the following code fragment, which uses the same connection
> parameters elsewhere to *successfully* to retrieve data from a
> database, so this doesn't appear to be a permissions problem with
> MySQL.
>
> However, nothing happens with inserts; no rows are added at all. All I
> get is a message form mysql_error() saying "Query was empty."
>
> Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
>
> echo "";
> echo "\nDebugging output:\n";
> echo "\tSQL: $sql\n";
> echo "\tError: ", mysql_error(), "\n";
> echo "\tLast insert ID: ", mysql_insert_id(), "\n";
> echo "\tResult: $result\n";
> echo "\n";
Your INSERT statement is contained in the variable $sql but you are using
$sql_query in the mysl_db_query function?
--
David Robley Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES Flinders University, SOUTH AUSTRALIA
URA Redneck if your funeral has more pickup trucks than cars.
Re: [PHP] INSERT problem with MySQL/PHP
Try the following,
INSERT INTO questions(user_id,objective,question,question_type)
VALUES('$uawr_idx', '$objective', '$question', '$question_type')
Define the rows you want to insert into.
Hope this helps!
Regards,
Ray
- Original Message -
From: "Todd A. Jacobs" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Monday, June 18, 2001 4:11 PM
Subject: [PHP] INSERT problem with MySQL/PHP
> PHP: 4.0.4pl1
> MySQL: 3.23.36-1
>
> I have the following code fragment, which uses the same connection
> parameters elsewhere to *successfully* to retrieve data from a database,
> so this doesn't appear to be a permissions problem with MySQL.
>
> However, nothing happens with inserts; no rows are added at all. All I get
> is a message form mysql_error() saying "Query was empty."
>
> Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
>
> echo "";
> echo "\nDebugging output:\n";
> echo "\tSQL: $sql\n";
> echo "\tError: ", mysql_error(), "\n";
> echo "\tLast insert ID: ", mysql_insert_id(), "\n";
> echo "\tResult: $result\n";
> echo "\n";
>
> --
> Todd A. Jacobs
> CodeGnome Consulting, LTD
Re: [PHP] INSERT problem with MySQL/PHP
Todd,
Did you echo $sql and examine it?
Did you try the statement at the mysql console?
Does the list of values exactly match the field list?
Did you try the alternate syntax
INSERT [LOW_PRIORITY | DELAYED] [IGNORE]
[INTO] tbl_name
SET col_name=expression, col_name=expression, ...
as in the MySQL docs?
I'm really curious about what $sql looks like when you echo it. I've been
surprised more than once.
Miles Thompson
At 04:11 PM 6/18/01 -0700, Todd A. Jacobs wrote:
>PHP: 4.0.4pl1
>MySQL: 3.23.36-1
>
>I have the following code fragment, which uses the same connection
>parameters elsewhere to *successfully* to retrieve data from a database,
>so this doesn't appear to be a permissions problem with MySQL.
>
>However, nothing happens with inserts; no rows are added at all. All I get
>is a message form mysql_error() saying "Query was empty."
>
>Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
>
> echo "";
> echo "\nDebugging output:\n";
> echo "\tSQL: $sql\n";
> echo "\tError: ", mysql_error(), "\n";
> echo "\tLast insert ID: ", mysql_insert_id(), "\n";
> echo "\tResult: $result\n";
> echo "\n";
>
>--
>Todd A. Jacobs
>CodeGnome Consulting, LTD
Re: [PHP] INSERT problem with MySQL/PHP
replace $result = mysql_db_query('item_db', $sql_query, $connection_id);
with $result = mysql_db_query('item_db', $sql, $connection_id); or just
mysql_query($sql);
- Original Message -
From: "Todd A. Jacobs" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Monday, June 18, 2001 4:11 PM
Subject: [PHP] INSERT problem with MySQL/PHP
> PHP: 4.0.4pl1
> MySQL: 3.23.36-1
>
> I have the following code fragment, which uses the same connection
> parameters elsewhere to *successfully* to retrieve data from a database,
> so this doesn't appear to be a permissions problem with MySQL.
>
> However, nothing happens with inserts; no rows are added at all. All I get
> is a message form mysql_error() saying "Query was empty."
>
> Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
>
> echo "";
> echo "\nDebugging output:\n";
> echo "\tSQL: $sql\n";
> echo "\tError: ", mysql_error(), "\n";
> echo "\tLast insert ID: ", mysql_insert_id(), "\n";
> echo "\tResult: $result\n";
> echo "\n";
>
> --
> Todd A. Jacobs
> CodeGnome Consulting, LTD
>
Re: [PHP] INSERT problem with MySQL/PHP
On Mon, 18 Jun 2001, Todd A. Jacobs wrote:
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
Thanks to all who answered. It was a simple mistake, but hard for the eye
to catch: I needed the query to use $sql, not $sql_query.
The program now works properly. Thank you.
--
Todd A. Jacobs
CodeGnome Consulting, LTD
RE: [PHP] INSERT problem with MySQL/PHP
> Can anyone tell me what might be wrong?
>
> $user_idx = 1;
> $objective = 1;
> $question = 'Foo';
> $question_type = 'singular';
>
> $connection_id = mysql_connect ('192.168.1.1', 'php', 'password')
> or die ("No connection.\n");
>
> $sql = "INSERT INTO question VALUES (NULL, $user_idx, $objective,
> '$question', '$question_type', NULL, NULL)";
>
> $result = mysql_db_query('item_db', $sql_query, $connection_id);
^^
I daresay this will be the problem since the SQL is in $sql.
Jason
