Parameter sublists [was: An ordering question]

2009-03-13 Thread Peter Pearson 
On Fri, 13 Mar 2009 18:56:30 +0100, Hrvoje Niksic  wrote:
[snip]
> a.sort(key=lambda (x, y): b[y - 1], reverse=True)

Huh?  I had no idea one could do this:

>>> def g( ( ( x, y ), z ) ):
...   return y
... 
>>> g( ((1,2),3) )
2

What should I have read to learn that trick?

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Re: Parameter sublists [was: An ordering question]

2009-03-13 Thread Chris Rebert 
On Fri, Mar 13, 2009 at 5:30 PM, Peter Pearson  wrote:
> On Fri, 13 Mar 2009 18:56:30 +0100, Hrvoje Niksic  wrote:
> [snip]
>> a.sort(key=lambda (x, y): b[y - 1], reverse=True)
>
> Huh?  I had no idea one could do this:
>
 def g( ( ( x, y ), z ) ):
> ...   return y
> ...
 g( ((1,2),3) )
> 2
>
> What should I have read to learn that trick?

Don't bother. It's been excised in Python 3.0.

Cheers,
Chris

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http://blog.rebertia.com
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Re: Parameter sublists [was: An ordering question]

2009-03-13 Thread Kottiyath 
On Mar 14, 5:39 am, Chris Rebert  wrote:
> On Fri, Mar 13, 2009 at 5:30 PM, Peter Pearson  
> wrote:
> > On Fri, 13 Mar 2009 18:56:30 +0100, Hrvoje Niksic  
> > wrote:
> > [snip]
> >> a.sort(key=lambda (x, y): b[y - 1], reverse=True)
>
> > Huh?  I had no idea one could do this:
>
>  def g( ( ( x, y ), z ) ):
> > ...   return y
> > ...
>  g( ((1,2),3) )
> > 2
>
> > What should I have read to learn that trick?
>
> Don't bother. It's been excised in Python 3.0.
>
> Cheers,
> Chris
>
> --
> I have a blog:http://blog.rebertia.com

Thank you very much.
These many solutions ?
I think programming is not my forte :-) :-)
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