Thank you very much Miguel ! I couldn't believe it was that easy.
Luis Vega.
--- On Wed, 3/10/10, Miguel Porto wrote:
From: Miguel Porto
Subject: Re: [R] Joining elements of an array into a single element
To: veg...@yahoo.com
Cc: r-help@r-project.org
Date: Wednesday, March 10, 2010, 8:57 PM
Hello,If you do this after the for loop, you'll get what you want:
paste(tre,collapse="")
(you can use whatever separator you want in the collapse argument)
But you don't even need the for loop, just do this instead of the for loop:
paste("con(",p," == ",c,", ",zest,", ",sep="",collapse="")
Best,Miguel
On Wed, Mar 10, 2010 at 11:44 AM, wrote:
Dear forum:
I've been trying like for hours but I cannot solve this. I wonder if you could
give me a hand.
I would like to combine the following elements of an array which I must
generate in order to get the syntax I need for another software, lets say:
c<-c(1:7)
zest<-c(12,34,45,132,56,23,6)
p<-"[foresnat2]"
for(i in 1:7){tre[i]<-paste("con(",p," == ",c[i],", ",zest[i],", ",sep="")}
[1] "con([foresnat2] == 1, 12, "
[1] "con([foresnat2] == 2, 34, "
[1] "con([foresnat2] == 3, 45, "
[1] "con([foresnat2] == 4, 132, "
[1] "con([foresnat2] == 5, 56, "
[1] "con([foresnat2] == 6, 23, "
[1] "con([foresnat2] == 7, 6, "
I would like the elements of the object "tre" to go one after another without
space (or with a character I design like for example "*" or "+" )like this:
[1] "con([foresnat2] == 1, 12, con([foresnat2] == 2, 34, con([foresnat2] == 3,
45, con... etc
I understand it could be done with the function "paste" invoking each of the
elements, but lets say they are not only 7 but 20 or 40 elements...
Is it possible? What can I do?
Thank you very much in advance.
Luis Vega
PD: Just in case: For the other software language i was talking about, the
usage of "con" is the same as "ifelse" in R, I'm trying to generate
a large embed ifelse(..., ..., ifelse(...,...,ifelse( entry. but with
what I'm requiring lines above should be enough I think.
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