Re: [R] Mandriva Spring 2007 and R
Thank you everyone for all of your suggestions!! I am going to try compiling R from the source- it should be the best exercise to broaden my understanding of Linux. Best. Jonathan. Roland Rau <[EMAIL PROTECTED]> wrote: Hi Jonathan, Jonathan Morse wrote: > I am new to Linux (not to R) and recently installed Mandriva Spring 2007 on > my partitioned hard drive. My next objective is to install R in the Linux > environment, unfortunately Mandriva is not one of the Linux distributions > available for download... Could someone please let me know which > distribution I should use? > One possibility is, of course, that you compile it yourself for your computer. Compiling R was my first shot at compiling programs when I was new to Linux, and it was not very difficult. It is described nicely in the R Installation Administration Manual. http://cran.r-project.org/doc/manuals/R-admin.html Basically, you only need to take care of the following steps to get you started: - did you download and unpack the source distribution (see section 1.1 of the manual)? - do you have the required tools installed (see section A.1 of the manual)? (C compiler, Fortran compiler, libreadline, libjpeg, libpng, tex/latex, Perl5, xorg-x11-dev) - compilation (see section 2.1 in the manual) I hope this helps? Best, Roland - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Mandriva Spring 2007 and R
I am new to Linux (not to R) and recently installed Mandriva Spring 2007 on my partitioned hard drive. My next objective is to install R in the Linux environment, unfortunately Mandriva is not one of the Linux distributions available for download... Could someone please let me know which distribution I should use? Thanks. Jonathan - Boardwalk for $500? In 2007? Ha! [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trimming a Data Set
That works nicely.
Thank you.
jim holtman <[EMAIL PROTECTED]> wrote: try this:
trim <- function(x,prop=.05) {
trimlow <-quantile(x,prob=(prop))
trimhigh <- quantile(x,prob=(1 - prop))
x[(x >= trimlow) & (x <= trimhigh)]
}
On 3/20/07, Jonathan Morse <[EMAIL PROTECTED]> wrote: Thanks for the rapid
response.
The inequality with the quantile trim works great, however I am in looking for
a two tailed trim. This could work if I could unite two series in a command
similar to the following:
trim <- function(x,prop=.05) {
trimlow <- x[x < quantile(x,prob=(1-prop))]
trimhigh <- x[x > quantile(x,prob=(prop))]
trimx <- intersect(trimlow, trimhigh)
return(trimx)
}
However the intersect function will not return repeated values, which is a
problem. Any thoughts??
Thanks.
Petr Klasterecky <[EMAIL PROTECTED]> wrote: If it is precise enough for you,
you can use
trim <- function(x,prop=.05) {
trimx <- x[x < quantile(x,prob=(1-prop))]
return(trimx)
}
Petr
Jonathan Morse napsal(a):
> Hi,
>
> I am trying to restrict a data set so as not to included outliers.
> Specifically, I would like to specify a percentage where a fraction of
> observations are eliminated from the data set, much in the same way that the
> trimmed mean function works - but leaving the restricted data set intact.
>
> I have been using a function which will restrict the data set using:
>> trim=function(x,p){
>> o=order(x)
>> xo=x[o]
>> n=length(xo)
>> tl=round(n*p)
>> print(xo[(tl+1):(n-tl)])}
>
> However I was wondering if anyone knew a more elegant and simple method to
> get the same result.
>
> Thanks in advance.
>
>
>
> -
> Don't pick lemons.
>
> [[alternative HTML version deleted]]
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Petr Klasterecky
Dept. of Probability and Statistics
Charles University in Prague
Czech Republic
-
TV dinner still cooling?
Check out "Tonight's Picks" on Yahoo! TV.
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
-
It's here! Your new message!
Get new email alerts with the free Yahoo! Toolbar.
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trimming a Data Set
Thanks for the rapid response.
The inequality with the quantile trim works great, however I am in looking for
a two tailed trim. This could work if I could unite two series in a command
similar to the following:
trim <- function(x,prop=.05) {
trimlow <- x[x < quantile(x,prob=(1-prop))]
trimhigh <- x[x > quantile(x,prob=(prop))]
trimx <- intersect(trimlow, trimhigh)
return(trimx)
}
However the intersect function will not return repeated values, which is a
problem. Any thoughts??
Thanks.
Petr Klasterecky <[EMAIL PROTECTED]> wrote: If it is precise enough for you,
you can use
trim <- function(x,prop=.05) {
trimx <- x[x < quantile(x,prob=(1-prop))]
return(trimx)
}
Petr
Jonathan Morse napsal(a):
> Hi,
>
> I am trying to restrict a data set so as not to included outliers.
> Specifically, I would like to specify a percentage where a fraction of
> observations are eliminated from the data set, much in the same way that the
> trimmed mean function works - but leaving the restricted data set intact.
>
> I have been using a function which will restrict the data set using:
>> trim=function(x,p){
>> o=order(x)
>> xo=x[o]
>> n=length(xo)
>> tl=round(n*p)
>> print(xo[(tl+1):(n-tl)])}
>
> However I was wondering if anyone knew a more elegant and simple method to
> get the same result.
>
> Thanks in advance.
>
>
>
> -
> Don't pick lemons.
>
> [[alternative HTML version deleted]]
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Petr Klasterecky
Dept. of Probability and Statistics
Charles University in Prague
Czech Republic
-
Be a PS3 game guru.
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trimming a Data Set
Thanks for the rapid response.
The inequality with the quantile trim works great, however I am in looking for
a two tailed trim. This could work if I could unite two series in a command
similar to the following:
trim <- function(x,prop=.05) {
trimlow <- x[x < quantile(x,prob=(1-prop))]
trimhigh <- x[x > quantile(x,prob=(prop))]
trimx <- intersect(trimlow, trimhigh)
return(trimx)
}
However the intersect function will not return repeated values, which is a
problem. Any thoughts??
Thanks.
Petr Klasterecky <[EMAIL PROTECTED]> wrote: If it is precise enough for you,
you can use
trim <- function(x,prop=.05) {
trimx <- x[x < quantile(x,prob=(1-prop))]
return(trimx)
}
Petr
Jonathan Morse napsal(a):
> Hi,
>
> I am trying to restrict a data set so as not to included outliers.
> Specifically, I would like to specify a percentage where a fraction of
> observations are eliminated from the data set, much in the same way that the
> trimmed mean function works - but leaving the restricted data set intact.
>
> I have been using a function which will restrict the data set using:
>> trim=function(x,p){
>> o=order(x)
>> xo=x[o]
>> n=length(xo)
>> tl=round(n*p)
>> print(xo[(tl+1):(n-tl)])}
>
> However I was wondering if anyone knew a more elegant and simple method to
> get the same result.
>
> Thanks in advance.
>
>
>
> -
> Don't pick lemons.
>
> [[alternative HTML version deleted]]
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Petr Klasterecky
Dept. of Probability and Statistics
Charles University in Prague
Czech Republic
-
TV dinner still cooling?
Check out "Tonight's Picks" on Yahoo! TV.
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Trimming a Data Set
Hi,
I am trying to restrict a data set so as not to included outliers.
Specifically, I would like to specify a percentage where a fraction of
observations are eliminated from the data set, much in the same way that the
trimmed mean function works - but leaving the restricted data set intact.
I have been using a function which will restrict the data set using:
> trim=function(x,p){
> o=order(x)
> xo=x[o]
> n=length(xo)
> tl=round(n*p)
> print(xo[(tl+1):(n-tl)])}
However I was wondering if anyone knew a more elegant and simple method to get
the same result.
Thanks in advance.
-
Don't pick lemons.
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
