On 09/08/2010 01:05 PM, Jack Kordas wrote:
When I try to use both aliases and labels, the results are not named
as expected.
Instead of being able to access the columns as label-name_column-
name it appears as original-table-name_numeric-sequence_column-
name
Thanks,
Jack
Sample code follows:
parent = Table('parent', metadata,
Column('id', INTEGER(), primary_key=True),
Column('name', VARCHAR(length=128)),
Column('first_id', INTEGER(),
ForeignKey(u'child.id')),
)
child = Table('child', metadata,
Column('id', INTEGER(), primary_key=True),
Column('name', VARCHAR(length=128))
)
def test_labels1(conn):
s = select([parent,child], use_labels=True)
s = s.where(parent.c.first_id==child.c.id)
return conn.execute(s).fetchone()
def test_alias1(conn):
firstchild = child.alias()
s = select([parent,firstchild], use_labels=True)
s = s.where(parent.c.first_id==firstchild.c.id)
return conn.execute(s).fetchone()
conn = engine.connect()
results = test_labels1(conn)
print results.parent_name
print results.child_name
results = test_alias1(conn)
print 'alias1 results: '
print results.parent_name
#print results.firstchild_name # expected this to work
print results.child_1_name # this worked instead
You need to set an explicit name for the alias to prevent SQLAlchemy
from generating an anonymous name[1]:
firstchild = child.alias(firstchild)
-Conor
[1]
http://www.sqlalchemy.org/docs/core/expression_api.html#sqlalchemy.sql.expression.FromClause.alias
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