You could make the __init__ take the filename:
def __init__(self, filename=None):
#do whatever
And then instantiate the object like:
x = someClass(filename=someFile)
Alternatively, you could make the Open function a module level function,
defined in someClass.py, but not in the actual class
definition.
There's also a way to do it with @staticmethod, but I haven't ever touched that.
Thanks,
Ryan
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Christian
Meesters
Sent: Monday, February 21, 2005 5:01 AM
To: tutor@python.org
Subject: [Tutor] Initializing with a call like: someClass.open(someFile)?
Hi
My cryptic subject is perhaps not sufficient - I'll try to make it a little
better:
Assume you'd like to write something like:
import someClass
x = someClass.open(someFile)
Here '.open' should read in the data and initialize the instance - with or
without calling __init__.
How is this to implement? Up to now I rather wrote something like x =
someClass(somePrepFunction(someFile)) where the return value of
somePrepFunction was used
to initialize x or called the conventional 'open' within __init__. But is there
no direct approach like
in my pseudo-code?
My problem is that if I simply define open as a method of someClass (with
def open(self,file_name):
#somecode
pass
) all I get is:
TypeError: unbound method open() must be called with someClass instance as
first argument
(got str instance instead)
Which is perfectly understandable. But what is a possible workaround? (Instead
of 'open' I could,
of course, better use some other keyword which is no Python keyword.)
Any hints?
Thanks a lot in advance.
Christian
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