Re: Login page + post login page .... OR Getting a page from a dispatcher
Hi Uli et al,
Is there a neater way to tidier way to extract the activation context
parameters from the Request than the way I'm doing it below? It assumes I've
already extracted the pageName from the Request path.
String path = request.getPath();
String[] activationContextParams = path.substring(pageName.length() +
1).split();
for (int i = 0; i activationContextParams.length; i++) {
if (activationContextParams[i].length() 0) {
activationContextParams[i] =
activationContextParams[i].substring(1);
}
}
Link pageAfterLoginLink =
pageRenderLinkSource.createPageRenderLinkWithContext(pageName,
(Object[]) activationContextParams);
Cheers,
Geoff
On 30/10/2009, at 5:53 AM, Ulrich Stärk wrote:
That's weird. It's exactly how I'm doing it:
PageCallbackContainer login = (PageCallbackContainer)
componentSource.getPage(Login.class);
login.setCallback(new PageCallback(pageName, pageActivationContext,
linkSource));
Link link = linkSource.createPageRenderLink(Login.class);
response.sendRedirect(link);
PageCallbackContainer is the interface implemented by the Login page class.
I'm calling it from inside a ComponentRequestFilter but that shouldn't matter.
Are you sure that Login really implements ILogin?
Cheers,
Uli
Am 29.10.2009 15:41 schrieb Gunnar Eketrapp:
Hum ... your advice seemed quite straighforward
By some reason I can't cast to the interface either ...
Weirdo ...
I have rebuild the project and restarted the APP since i thought that the
old Login.class could spoke me ...
java.lang.ClassCastException com.tellpoker.pages.Login cannot be cast to
com.tellpoker.pages.ILogin
Stack trace
-
com.tellpoker.services.ProtectedPageGateKeeper.checkAccess(ProtectedPageGateKeeper.java:147)
-
com.tellpoker.services.ProtectedPageGateKeeper.dispatch(ProtectedPageGateKeeper.java:64)
- $Dispatcher_124a0b9d291.dispatch($Dispatcher_124a0b9d291.java)
- $Dispatcher_124a0b9d286.dispatch($Dispatcher_124a0b9d286.java)
-
org.apache.tapestry5.services.TapestryModule$RequestHandlerTerminator.service(TapestryModule.java:245)
- com.tellpoker.services.AppModule$1.service(AppModule.java:144)
- $RequestFilter_124a0b9d285.service($RequestFilter_124a0b9d285.java)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.RequestErrorFilter.service(RequestErrorFilter.java:26)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$4.service(TapestryModule.java:778)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$3.service(TapestryModule.java:767)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.StaticFilesFilter.service(StaticFilesFilter.java:85)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:90)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:81)
-
org.apache.tapestry5.ioc.internal.util.ConcurrentBarrier.withRead(ConcurrentBarrier.java:85)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter.service(CheckForUpdatesFilter.java:103)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
- $RequestHandler_124a0b9d27c.service($RequestHandler_124a0b9d27c.java)
-
org.apache.tapestry5.services.TapestryModule$HttpServletRequestHandlerTerminator.service(TapestryModule.java:197)
- org.apache.tapestry5.internal.gzip.GZipFilter.service(GZipFilter.java:53)
-
$HttpServletRequestHandler_124a0b9d27e.service($HttpServletRequestHandler_124a0b9d27e.java)
-
org.apache.tapestry5.internal.services.IgnoredPathsFilter.service(IgnoredPathsFilter.java:62)
-
$HttpServletRequestFilter_124a0b9d27b.service($HttpServletRequestFilter_124a0b9d27b.java)
-
$HttpServletRequestHandler_124a0b9d27e.service($HttpServletRequestHandler_124a0b9d27e.java)
-
org.apache.tapestry5.services.TapestryModule$2.service(TapestryModule.java:726)
-
$HttpServletRequestHandler_124a0b9d27e.service($HttpServletRequestHandler_124a0b9d27e.java)
-
$HttpServletRequestHandler_124a0b9d279.service($HttpServletRequestHandler_124a0b9d279.java)
- org.apache.tapestry5.TapestryFilter.doFilter(TapestryFilter.java:127)
2009/10/29 Gunnar Eketrapp gunnar.eketr...@gmail.com
Thanks a lot !!!
2009/10/29 Ulrich Stärk u...@spielviel.de
Have your page implement an interface that provides methods for setting the
desired information and cast the result from componentSource.getPage() to
that interface.
The reason behind this is that the thing returned from componentSource
Re: [T5] Adding/removing entries to messages
Sorry, I missed the point, my solution only works for labels used in
grids etc
On 06.02.2010 13:51, Nuno Ferreira wrote:
I'll definitely try that. And using a cache I could give my users the
functionality to change at runtime the label translations, which I'm
planning anyway since google translate isn't always perfect.
On 6 February 2010 12:19, Alexander Muthmannamuthm...@dev-eth0.de wrote:
Fast idea:
You could override the existing provider for Message-Entries and add a
function to look at google translate if the requestes label was not found.
The service would be ComponentDefaultProvider and the needed method
defaultLabel:
public String defaultLabel(ComponentResources resources)
{
Defense.notNull(resources, resources);
String componentId = resources.getId();
String key = componentId + -label;
Messages containerMessages =
resources.getContainerResources().getMessages();
if (containerMessages.contains(key)) return
containerMessages.get(key);
\\here you can check google translate
return TapestryInternalUtils.toUserPresentable(componentId);
}
On the marked position you could add a new cache for already used labels...
On 06.02.2010 13:12, Nuno Ferreira wrote:
Hi,
I would like to know if there is a way to programatically add and remove
an
entry from a messages catalog.
The only way I see how to do this is to write to the file
app_{locale}.properties, but I would like a cleaner way if there is one.
I want to use google translate to automatically fill every catalog, and
would love to hear there is something like
messages.add(translation,locale)
:)
Thanks in advance,
Nuno Ferreira
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Re: Login page + post login page .... OR Getting a page from a dispatcher
There are several ways, depending on what you are doing.
If inside a ComponentRequestHandler's handlePageRender() method, you can
ask the PageRenderRequestParameters for getActivationContext(). If you
are handling a component event in handleComponentEvent(), just ask the
ComponentEventRequestParameters for getEventContext() or
getPageActivationContext() (depending on what you need).
PageRenderRequestParameters and ComponentEventRequestParameters are also
available in a PageRenderRequestHandler or a ComponentEventRequestHandler.
If you are not inside one of these handlers, try injecting the
ContextPathEncoder service and call its decodePath() method.
HTH,
Uli
Geoff Callender schrieb:
Hi Uli et al,
Is there a neater way to tidier way to extract the activation context
parameters from the Request than the way I'm doing it below? It assumes I've
already extracted the pageName from the Request path.
String path = request.getPath();
String[] activationContextParams = path.substring(pageName.length() +
1).split();
for (int i = 0; i activationContextParams.length; i++) {
if (activationContextParams[i].length() 0) {
activationContextParams[i] =
activationContextParams[i].substring(1);
}
}
Link pageAfterLoginLink =
pageRenderLinkSource.createPageRenderLinkWithContext(pageName,
(Object[]) activationContextParams);
Cheers,
Geoff
On 30/10/2009, at 5:53 AM, Ulrich Stärk wrote:
That's weird. It's exactly how I'm doing it:
PageCallbackContainer login = (PageCallbackContainer)
componentSource.getPage(Login.class);
login.setCallback(new PageCallback(pageName, pageActivationContext,
linkSource));
Link link = linkSource.createPageRenderLink(Login.class);
response.sendRedirect(link);
PageCallbackContainer is the interface implemented by the Login page class. I'm
calling it from inside a ComponentRequestFilter but that shouldn't matter.
Are you sure that Login really implements ILogin?
Cheers,
Uli
Am 29.10.2009 15:41 schrieb Gunnar Eketrapp:
Hum ... your advice seemed quite straighforward
By some reason I can't cast to the interface either ...
Weirdo ...
I have rebuild the project and restarted the APP since i thought that the
old Login.class could spoke me ...
java.lang.ClassCastException com.tellpoker.pages.Login cannot be cast to
com.tellpoker.pages.ILogin
Stack trace
-
com.tellpoker.services.ProtectedPageGateKeeper.checkAccess(ProtectedPageGateKeeper.java:147)
-
com.tellpoker.services.ProtectedPageGateKeeper.dispatch(ProtectedPageGateKeeper.java:64)
- $Dispatcher_124a0b9d291.dispatch($Dispatcher_124a0b9d291.java)
- $Dispatcher_124a0b9d286.dispatch($Dispatcher_124a0b9d286.java)
-
org.apache.tapestry5.services.TapestryModule$RequestHandlerTerminator.service(TapestryModule.java:245)
- com.tellpoker.services.AppModule$1.service(AppModule.java:144)
- $RequestFilter_124a0b9d285.service($RequestFilter_124a0b9d285.java)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.RequestErrorFilter.service(RequestErrorFilter.java:26)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$4.service(TapestryModule.java:778)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$3.service(TapestryModule.java:767)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.StaticFilesFilter.service(StaticFilesFilter.java:85)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:90)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:81)
-
org.apache.tapestry5.ioc.internal.util.ConcurrentBarrier.withRead(ConcurrentBarrier.java:85)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter.service(CheckForUpdatesFilter.java:103)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
- $RequestHandler_124a0b9d27c.service($RequestHandler_124a0b9d27c.java)
-
org.apache.tapestry5.services.TapestryModule$HttpServletRequestHandlerTerminator.service(TapestryModule.java:197)
- org.apache.tapestry5.internal.gzip.GZipFilter.service(GZipFilter.java:53)
-
$HttpServletRequestHandler_124a0b9d27e.service($HttpServletRequestHandler_124a0b9d27e.java)
-
org.apache.tapestry5.internal.services.IgnoredPathsFilter.service(IgnoredPathsFilter.java:62)
-
$HttpServletRequestFilter_124a0b9d27b.service($HttpServletRequestFilter_124a0b9d27b.java)
-
$HttpServletRequestHandler_124a0b9d27e.service($HttpServletRequestHandler_124a0b9d27e.java)
-
Re: T4: forward browser to an external web site
Yes I had already tought of a solution like taht but I was hoping for a
clean tapestry solution like the you suggested me with the link.
Thanks anyway.
Would instead be possible with T5?
Martin Strand ha scritto:
For POST requests, your initial idea is the way to go:
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far better to
have my page class.
So you'll render a form (no need to use the Form component for this)
form action=http://www.example.com/; id=myForm method=post
input type=hidden name=someParameter value=someValue/
/form
If you want to submit the form automatically without having your user
click anything, hide the form with CSS and use a script similar to
this at the bottom of your page:
...
...
script
document.getElementById(myForm).submit();
/script
/body
/html
On Sat, 06 Feb 2010 19:30:21 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Thanks Martin: it worked.
But what I could do in case I had to submit a form accepting only POST
method in the form?
Ivano Luberti ha scritto:
I will try that: for whatever reason I was convinced that I had to
submit a form and not simply a link.
But checking twice the docs of the web site I have to forward to, I see
I can use a link.
Thanks for now
Martin Strand ha scritto:
If you just want to redirect the client to another URL, return an
ILink from your form listener:
public ILink formSubmitListener()
{
// Do work
// ...
return new StaticLink(http://www.example.com/;);
}
Martin
On Wed, 03 Feb 2010 10:39:23 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Hello, I'm trying to solve the following problem using T4.1.6.
I want to have the user submit a form , perform some operation in the
page class and then forward the user to an external web site.
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far better to
have my page class.
I have tried using a service and HttpClient package but it return and
HttpResponse and I'm not able to convert it to a WebResponse.
Any suggestion?
-
To unsubscribe, e-mail: users-unsubscr...@tapestry.apache.org
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--
==
dott. Ivano Mario Luberti
Archimede Informatica societa' cooperativa a r. l.
Sede Operativa
Via Gereschi 36 - 56126- Pisa
tel.: +39-050- 580959
tel/fax: +39-050-9711344
web: www.archicoop.it
==
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Re: T4: forward browser to an external web site
This has nothing to do with Tapestry, it's how the HTTP protocol works.
There's just no response you can send which tells the client to POST data to
another URL. Instead you send a short program which performs the POST and hope
your client executes that program - that's the script solution.
On Sun, 07 Feb 2010 18:37:15 +0100, Ivano Luberti lube...@archicoop.it wrote:
Yes I had already tought of a solution like taht but I was hoping for a
clean tapestry solution like the you suggested me with the link.
Thanks anyway.
Would instead be possible with T5?
Martin Strand ha scritto:
For POST requests, your initial idea is the way to go:
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far better to
have my page class.
So you'll render a form (no need to use the Form component for this)
form action=http://www.example.com/; id=myForm method=post
input type=hidden name=someParameter value=someValue/
/form
If you want to submit the form automatically without having your user
click anything, hide the form with CSS and use a script similar to
this at the bottom of your page:
...
...
script
document.getElementById(myForm).submit();
/script
/body
/html
On Sat, 06 Feb 2010 19:30:21 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Thanks Martin: it worked.
But what I could do in case I had to submit a form accepting only POST
method in the form?
Ivano Luberti ha scritto:
I will try that: for whatever reason I was convinced that I had to
submit a form and not simply a link.
But checking twice the docs of the web site I have to forward to, I see
I can use a link.
Thanks for now
Martin Strand ha scritto:
If you just want to redirect the client to another URL, return an
ILink from your form listener:
public ILink formSubmitListener()
{
// Do work
// ...
return new StaticLink(http://www.example.com/;);
}
Martin
On Wed, 03 Feb 2010 10:39:23 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Hello, I'm trying to solve the following problem using T4.1.6.
I want to have the user submit a form , perform some operation in the
page class and then forward the user to an external web site.
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far better to
have my page class.
I have tried using a service and HttpClient package but it return and
HttpResponse and I'm not able to convert it to a WebResponse.
Any suggestion?
-
To unsubscribe, e-mail: users-unsubscr...@tapestry.apache.org
For additional commands, e-mail: users-h...@tapestry.apache.org
Re: T4: forward browser to an external web site
I know, but a was hoping for some kind of forward to external web site
mechanism.
It shouldn't be impossible to build something like that using HttpClient
or some similar package
Martin Strand ha scritto:
This has nothing to do with Tapestry, it's how the HTTP protocol works.
There's just no response you can send which tells the client to POST
data to another URL. Instead you send a short program which performs
the POST and hope your client executes that program - that's the
script solution.
On Sun, 07 Feb 2010 18:37:15 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Yes I had already tought of a solution like taht but I was hoping for a
clean tapestry solution like the you suggested me with the link.
Thanks anyway.
Would instead be possible with T5?
Martin Strand ha scritto:
For POST requests, your initial idea is the way to go:
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far
better to
have my page class.
So you'll render a form (no need to use the Form component for this)
form action=http://www.example.com/; id=myForm method=post
input type=hidden name=someParameter value=someValue/
/form
If you want to submit the form automatically without having your user
click anything, hide the form with CSS and use a script similar to
this at the bottom of your page:
...
...
script
document.getElementById(myForm).submit();
/script
/body
/html
On Sat, 06 Feb 2010 19:30:21 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Thanks Martin: it worked.
But what I could do in case I had to submit a form accepting only POST
method in the form?
Ivano Luberti ha scritto:
I will try that: for whatever reason I was convinced that I had to
submit a form and not simply a link.
But checking twice the docs of the web site I have to forward to,
I see
I can use a link.
Thanks for now
Martin Strand ha scritto:
If you just want to redirect the client to another URL, return an
ILink from your form listener:
public ILink formSubmitListener()
{
// Do work
// ...
return new StaticLink(http://www.example.com/;);
}
Martin
On Wed, 03 Feb 2010 10:39:23 +0100, Ivano Luberti
lube...@archicoop.it wrote:
Hello, I'm trying to solve the following problem using T4.1.6.
I want to have the user submit a form , perform some operation
in the
page class and then forward the user to an external web site.
Of course I can return to the new user a new page with a form that
has
an action that points to the web site, but it would be far
better to
have my page class.
I have tried using a service and HttpClient package but it
return and
HttpResponse and I'm not able to convert it to a WebResponse.
Any suggestion?
-
To unsubscribe, e-mail: users-unsubscr...@tapestry.apache.org
For additional commands, e-mail: users-h...@tapestry.apache.org
--
==
dott. Ivano Mario Luberti
Archimede Informatica societa' cooperativa a r. l.
Sede Operativa
Via Gereschi 36 - 56126- Pisa
tel.: +39-050- 580959
tel/fax: +39-050-9711344
web: www.archicoop.it
==
-
To unsubscribe, e-mail: users-unsubscr...@tapestry.apache.org
For additional commands, e-mail: users-h...@tapestry.apache.org
Re: Login page + post login page .... OR Getting a page from a dispatcher
Thanks, I'll give that a try. BTW, the code I posted earlier doesn't work, but
this seems to:
String path = request.getPath();
String[] activationContextParams = path.substring(pageName.length() +
2).split(\\/);
Link pageAfterLoginLink =
pageRenderLinkSource.createPageRenderLinkWithContext(pageName,
(Object[]) activationContextParams);
Still, I'd prefer to have Tapestry figure out the activation context rather
than me.
On 07/02/2010, at 10:27 PM, Ulrich Stärk wrote:
There are several ways, depending on what you are doing.
If inside a ComponentRequestHandler's handlePageRender() method, you can ask
the PageRenderRequestParameters for getActivationContext(). If you are
handling a component event in handleComponentEvent(), just ask the
ComponentEventRequestParameters for getEventContext() or
getPageActivationContext() (depending on what you need).
PageRenderRequestParameters and ComponentEventRequestParameters are also
available in a PageRenderRequestHandler or a ComponentEventRequestHandler.
If you are not inside one of these handlers, try injecting the
ContextPathEncoder service and call its decodePath() method.
HTH,
Uli
Geoff Callender schrieb:
Hi Uli et al,
Is there a neater way to tidier way to extract the activation context
parameters from the Request than the way I'm doing it below? It assumes I've
already extracted the pageName from the Request path.
String path = request.getPath();
String[] activationContextParams = path.substring(pageName.length() +
1).split();
for (int i = 0; i activationContextParams.length; i++) {
if (activationContextParams[i].length() 0) {
activationContextParams[i] =
activationContextParams[i].substring(1);
}
}
Link pageAfterLoginLink =
pageRenderLinkSource.createPageRenderLinkWithContext(pageName,
(Object[]) activationContextParams);
Cheers,
Geoff
On 30/10/2009, at 5:53 AM, Ulrich Stärk wrote:
That's weird. It's exactly how I'm doing it:
PageCallbackContainer login = (PageCallbackContainer)
componentSource.getPage(Login.class);
login.setCallback(new PageCallback(pageName, pageActivationContext,
linkSource));
Link link = linkSource.createPageRenderLink(Login.class);
response.sendRedirect(link);
PageCallbackContainer is the interface implemented by the Login page class.
I'm calling it from inside a ComponentRequestFilter but that shouldn't
matter.
Are you sure that Login really implements ILogin?
Cheers,
Uli
Am 29.10.2009 15:41 schrieb Gunnar Eketrapp:
Hum ... your advice seemed quite straighforward
By some reason I can't cast to the interface either ...
Weirdo ...
I have rebuild the project and restarted the APP since i thought that the
old Login.class could spoke me ...
java.lang.ClassCastException com.tellpoker.pages.Login cannot be cast to
com.tellpoker.pages.ILogin
Stack trace
-
com.tellpoker.services.ProtectedPageGateKeeper.checkAccess(ProtectedPageGateKeeper.java:147)
-
com.tellpoker.services.ProtectedPageGateKeeper.dispatch(ProtectedPageGateKeeper.java:64)
- $Dispatcher_124a0b9d291.dispatch($Dispatcher_124a0b9d291.java)
- $Dispatcher_124a0b9d286.dispatch($Dispatcher_124a0b9d286.java)
-
org.apache.tapestry5.services.TapestryModule$RequestHandlerTerminator.service(TapestryModule.java:245)
- com.tellpoker.services.AppModule$1.service(AppModule.java:144)
- $RequestFilter_124a0b9d285.service($RequestFilter_124a0b9d285.java)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.RequestErrorFilter.service(RequestErrorFilter.java:26)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$4.service(TapestryModule.java:778)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.services.TapestryModule$3.service(TapestryModule.java:767)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.StaticFilesFilter.service(StaticFilesFilter.java:85)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:90)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter$2.invoke(CheckForUpdatesFilter.java:81)
-
org.apache.tapestry5.ioc.internal.util.ConcurrentBarrier.withRead(ConcurrentBarrier.java:85)
-
org.apache.tapestry5.internal.services.CheckForUpdatesFilter.service(CheckForUpdatesFilter.java:103)
- $RequestHandler_124a0b9d287.service($RequestHandler_124a0b9d287.java)
- $RequestHandler_124a0b9d27c.service($RequestHandler_124a0b9d27c.java)
-
Updating Hibernate Entites
Hello List,
i'm trying to update an Hibernate-Object but alway get an a different object
with the same identifier value was already associated with the session:
Exception.
My Form-Code looks like:
@Inject
private ConfigurationDAO configDAO;
@Persist
@Property
private Configuration config;
void onSuccessFromConfigForm(){
config.setEditDate(new Date());
configDAO.doSave(config);
}
void onActivate(Long configId){
config=configDAO.doRetrieve(configId,false);
}
void onActivate(){
configs = configDAO.findAll();
if(config==null)
config=new de.leomedia.leotipp.model.Configuration();
}
can anyone give me a lead into the right direction?
thanks, Dominik
