Re: Replacing '%' in a text file
--- Tim Chase <[EMAIL PROTECTED]> wrote:
> > I have to replace every occurrence of % in a file
> with
> > % |. I have been effectively replacing text using
> the
> > following construct:
> >
> > :%s/\/replacement/g
> >
> > However when I try to do the following:
> >
> > :%s/\<%\>/% |/g
> >
> > I am greeted by an error message. Obviously, the %
> > character needs to be treated differently for
> being
> > replaced. Escap sequence?
>
> The error message returned should give a clue
> regarding the
> problem ("E486: Pattern not found: \<%\>"). Your
> pattern
> "\" works well for words, ensuring that you
> don't find
> them as a sub-portion of some other word (such as
> finding the
> "foo" in "food", "snafoo", or "confoosion").
> However, the "\<"
> and "\>" tokens require a transition from a
> non-word-character to
> a word-character (or vice-versa). The "%"
> character, by default,
> is not a key-word character (though this can be
> altered by
> changing the 'iskeyword' setting).
>
> Unless there is some context in which you *don't*
> want to replace
> a "%" with "% |", you can just use
>
> :%s/%/% |/g
>
> without the "\<" and "\>" markers. You can read
> more about the
> problematic operators at
>
> :help /\<
>
> or making them part of the set of characters that
> constitute a
> keyword, by reading at
>
> :help 'iskeyword'
>
> HTH,
>
> -tim
>
Thanks. The problem is now resolved.
--
Muhammad Farooq-i-Azam
__
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Re: Replacing '%' in a text file
Hello, --- "A.J.Mechelynck" <[EMAIL PROTECTED]> wrote: > Muhammad Farooq-i-Azam wrote: > > I have to replace every occurrence of % in a file with > > % |. I have been effectively replacing text using the > > following construct: > > > > :%s/\/replacement/g > > > > However when I try to do the following: > > > > :%s/\<%\>/% |/g A.J. is right, the \< and \> won't work because there's no word boundary there. Are you trying to say 'replace % when surrounded by whitespace?' If so, you could use: :%s/\s\@<[EMAIL PROTECTED]/% |/g regards, Peter On Yahoo!7 Men's Health: What music do you want to hear on Men's Health Radio? http://www.menshealthmagazine.com.au/
Re: Replacing '%' in a text file
Muhammad Farooq-i-Azam wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\/replacement/g However when I try to do the following: :%s/\<%\>/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam Which message do you encounter? If it's "E486: Pattern not found: \<%\>" it means that Vim doesn't find a match. I guess the boundary between space and %, or % and space, is not seen as a word boundary. What is 'iskeyword' set to? By default, nothing lower than 48 (0x30 i.e., the digit zero) is a keyword character. Now % is 0x25, i.e., it is not included. Thus it is not seen as part of a word, and therefore it cannot be preceded by a begin-of word or followed by an end-of-word. I suggest the following code snippet: let save_isk = &isk setlocal isk+=% %s/\<%\>/% |/g let &l:isk = save_isk If you can afford to replace every percent sign regardless of what precedes or follows it, you can do simply :%s/%/% |/g Best regards, Tony.
Re: Replacing '%' in a text file
I create a test file and was able to replace all % with % | by doing this: :%s/%/% |/g You shouldn't need to escape the % Muhammad Farooq-i-Azam wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\/replacement/g However when I try to do the following: :%s/\<%\>/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com -- Scot P. Floess 27 Lake Royale Louisburg, NC 27549 252-478-8087 (Home) 919-754-4592 (Work) Chief Architect JPlate http://sourceforge.net/projects/jplate Chief Architect JavaPIM http://sourceforge.net/projects/javapim
Re: Replacing '%' in a text file
I have to replace every occurrence of % in a file with
% |. I have been effectively replacing text using the
following construct:
:%s/\/replacement/g
However when I try to do the following:
:%s/\<%\>/% |/g
I am greeted by an error message. Obviously, the %
character needs to be treated differently for being
replaced. Escap sequence?
The error message returned should give a clue regarding the
problem ("E486: Pattern not found: \<%\>"). Your pattern
"\" works well for words, ensuring that you don't find
them as a sub-portion of some other word (such as finding the
"foo" in "food", "snafoo", or "confoosion"). However, the "\<"
and "\>" tokens require a transition from a non-word-character to
a word-character (or vice-versa). The "%" character, by default,
is not a key-word character (though this can be altered by
changing the 'iskeyword' setting).
Unless there is some context in which you *don't* want to replace
a "%" with "% |", you can just use
:%s/%/% |/g
without the "\<" and "\>" markers. You can read more about the
problematic operators at
:help /\<
or making them part of the set of characters that constitute a
keyword, by reading at
:help 'iskeyword'
HTH,
-tim
Re: Replacing '%' in a text file
Hi, Muhammad Farooq-i-Azam wrote: > > I have to replace every occurrence of % in a file with > % |. I have been effectively replacing text using the > following construct: > > :%s/\/replacement/g > > However when I try to do the following: > > :%s/\<%\>/% |/g > > I am greeted by an error message. Obviously, the % > character needs to be treated differently for being > replaced. Escap sequence? I cannot figure out how to > do it. May be trivial for the gurus here. I will be > thankful for a hint. normally % is not included in the 'iskeyword' option so it is not considered part of a word. Therefore there can not be the beginning of a word right in front of %. The same is for true for the end of a word immediately after a %. You either have to include % in the 'iskeyword' option by issuing a :set iskeyword+=% before executing your substitute command or use :%s/%/% |/g without '\<' and '\>', respectively. Regards, Jürgen -- Sometimes I think the surest sign that intelligent life exists elsewhere in the universe is that none of it has tried to contact us. (Calvin)
Replacing '%' in a text file
I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\/replacement/g However when I try to do the following: :%s/\<%\>/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
