aren't you missing the db. before table?
like
def something():
grilla = SQLFORM.smartgrid(db.table_1)
and then for the orderby statement should be:
def something():
grilla = SQLFORM.smartgrid(db.table_1, orderby=db.table_1.field)
that should work.
> Hello
>
> Suppose we have the following:
>
> #Model:
> table_1 = db.define_table('table1',
> Field('name'),
> )
>
>
>
> table_2 = db.define_table('table2',
> Field('field1'),
> Field('field2', table_1),
> )
>
>
> #Controller:
>
> def something():
> grilla = SQLFORM.smartgrid(table_1)
>
>
>
> this shows me the grid with records from table1 and a link to another
> grid with table2 records. This is correct.
>
> But if I do the following:
>
> def something():
> grilla = SQLFORM.smartgrid(table_1, orderby= table_1)
>
>
> The first grid shows good and well ordered, but when trying to
> display records from table2 through the link, can't get the records
> because it is sort of a field belonging to table1
>
> *Query Not Supported: no such column: table1.name*
> *
> *
>
> Jose
>
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