Re: interesting JAPH, how does this work?

2002-01-11 Thread zentara
On 10 Jan 2002 18:10:20 -0500, [EMAIL PROTECTED] (Michael R. Wolf) wrote: >[EMAIL PROTECTED] (Zentara) writes: > >> I get it, so "perl" equals 285075 in a base24 number >> system, with the alphabet as it's units. > >24? What's 24? There are _26_ letters in the alphabet! Or >was "24" a base _11

Re: interesting JAPH, how does this work?

2002-01-10 Thread Michael R. Wolf
[EMAIL PROTECTED] (Zentara) writes: > I get it, so "perl" equals 285075 in a base24 number > system, with the alphabet as it's units. 24? What's 24? There are _26_ letters in the alphabet! Or was "24" a base _11_ number? And if so, what extra digit were you using other than your fingers? :-

Re: interesting JAPH, how does this work?

2002-01-10 Thread Randal L. Schwartz
> "Zentara" == Zentara <[EMAIL PROTECTED]> writes: Zentara> I get it, so "perl" equals 285075 in a base24 number system, Zentara> with the alphabet as it's units. There are only 24 letters in your alphabet? :) -- Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095

RE: interesting JAPH, how does this work?

2002-01-10 Thread Hanson, Robert
own addition and subtraction routines so that $a + $b added letters instead of number (or both letters and numbers). Rob -Original Message- From: zentara [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 10, 2002 3:51 PM To: [EMAIL PROTECTED] Subject: Re: interesting JAPH, how does this

Re: interesting JAPH, how does this work?

2002-01-10 Thread zentara
On Thu, 10 Jan 2002 12:11:53 -0500, [EMAIL PROTECTED] (Robert Hanson) wrote: >You can increment letters just like you increment numbers. >$x = "a"; >$x++; >print $x; # prints "b" > >And the letter "z" incremented becomes "aa". > >$x = "z"; >$x++; >print $x; # prints "aa" > >So here is the script.

RE: interesting JAPH, how does this work?

2002-01-10 Thread Stout, Joel R
A"; > -Original Message- > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] > Sent: Thursday, January 10, 2002 9:47 AM > To: Hanson, Robert > Cc: [EMAIL PROTECTED]; 'zentara' > Subject: RE: interesting JAPH, how does this work? > > > >

Re: interesting JAPH, how does this work?

2002-01-10 Thread Jon Molin
[EMAIL PROTECTED] wrote: > > Try this: > > #!/opt/local/bin/perl > #!/usr/bin/perl > my $A="a"; > for(0..285074){ > $A++; > print" $A:"; perhaps you should consider NOT printing that 285074 times? would kinda flood the term :) > } > print"\n\n$A\n"; > > --

RE: interesting JAPH, how does this work?

2002-01-10 Thread William.Ampeh
Try this: #!/opt/local/bin/perl #!/usr/bin/perl my $A="a"; for(0..285074){ $A++; print" $A:"; } print"\n\n$A\n"; -- This reemphasizes a mail I just read from someone on this list about the need to write "clearly readable" codes. ___

Re: interesting JAPH, how does this work?

2002-01-10 Thread Luke Bakken
C:\users>perl -e "$A=qq(a);for(0..285074){$A++}print qq($A\n);" perl C:\users>perl -e "$A=qq(a);for(0..28){$A++}print qq($A\n);" ad C:\users>perl -e "$A=qq(a);for(0..2){$A++}print qq($A\n);" d C:\users>perl -e "$A=qq(a);for(0..1){$A++}print qq($A\n);" c C:\users>perl -e "$A=qq(a);for(0){$A++}p

RE: interesting JAPH, how does this work?

2002-01-10 Thread Hanson, Robert
quot;a"; # assign "a" to $A. for(0..285074){$A++;} # increment $A 285,074 times print"$A\n"; # prints the new value Rob -Original Message- From: zentara [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 10, 2002 12:01 PM To: [EMAIL PROTECTED] Subject: interesting JA

interesting JAPH, how does this work?

2002-01-10 Thread zentara
Hi, I saw this on perlmonks.org. I can't understand how it works. Can anyone enlighten me? #!/usr/bin/perl my $A="a"; for(0..285074){$A++;}print"$A\n";