Hi again, my dear baker friends.
Until now, when I've written this in a controller:
$paginatedQuery = $this-paginate($this-modelClass);
I've coded this in a view to access the information that it returns
(inside a foreach loop, of course):
$row['ModelName']['user_login']
That is,
How about
$modelName = key($this-params['paging']);
That should do the trick.
hth
grigri
On Jul 20, 11:47 am, jordicakephp jordicake...@gmail.com wrote:
Hi again, my dear baker friends.
Until now, when I've written this in a controller:
$paginatedQuery = $this-paginate($this-modelClass);
Thanks a lot, grigri.
Your trick worked perfectly and I didn't know I can access the
parameters of a view in the same way I access the parameters of a
controller.
What a disaster!
Regards.
On 20 jul, 14:19, grigri j...@hendersonwebdesign.com wrote:
How about
$modelName =
