Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-24 Thread euromark
it does cause the problem :) usually a good IDEA would automatically display a parse error On 24 Dez., 02:52, Geoff Douglas drdouglas...@gmail.com wrote: Under the logged in condition... you are using double quotes twice... could cause a problem. -- Our newest site for the community: CakePHP

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-24 Thread JonStark
Indeed, stupid mistake... Thanks again ! I need to be more careful. This works : ?php $addlink = $this-Html-url('/items/add'); if ($this-Session-check('Auth.User.id')) { echo ( div class='well' style='padding:

Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread JonStark
I want to do this on cake 2.0.4 (new to cake), but this does'nt work: ?php if ($session-read('Auth')) { echo(logged); } else { echo(not logged); } ? Thanks a lot for your help ! -- Our newest

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread euromark
$session was already outdated in 1.3 $this-Session is the correct usage On 23 Dez., 17:26, JonStark jean...@gmail.com wrote: I want to do this on cake 2.0.4 (new to cake), but this does'nt work:         ?php          if ($session-read('Auth')) {                 echo(logged);              

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread JonStark
I never used previous versions, I found this by searching a little on the net. So it's more like : ?php if ($this-Session('Auth')) { echo(logged); } else { echo(not logged); } ? ? Thanks a lot for

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread euromark
ok, that makes sense. no - the method call stays the same! btw: most cake developers would check on the id specifically: if ($this-Session-check('Auth.User.id')) {} On 23 Dez., 19:51, JonStark jean...@gmail.com wrote: I never used previous versions, I found this by searching a little on the

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread euromark
more can be found here: http://book.cakephp.org/2.0/en/core-libraries/helpers/session.html?highlight=session#SessionHelper On 23 Dez., 20:01, euromark dereurom...@googlemail.com wrote: ok, that makes sense. no - the method call stays the same! btw: most cake developers would check on the id

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread JonStark
Thanks a lot ! Now it works, and more importantly I understand why ! Thanks a lot for your time. On 23 déc, 20:02, euromark dereurom...@googlemail.com wrote: more can be found here:http://book.cakephp.org/2.0/en/core-libraries/helpers/session.html?hi... On 23 Dez., 20:01, euromark

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread JonStark
Just a last question : I can echo this : ?php if ($this-Session-check('Auth.User.id')) { echo( Logged in ) } else { echo (Not logged in); } ? but this

Re: Cake 2.0.4 : how to display logout if logged, else display login

2011-12-23 Thread Geoff Douglas
Under the logged in condition... you are using double quotes twice... could cause a problem. -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related