On 09/11/2014 09:18 AM, andre wrote:
> I am not sure. b is C but everything not in super class B is hidden.
> Using cast I can cast b to a full C.
>
> The cast "cast(C)b" has the same information about b like the cast
> "cast(A)b": The memory area of b knows compatitibility to C and also the
> al
I am not sure. b is C but everything not in super class B is
hidden.
Using cast I can cast b to a full C.
The cast "cast(C)b" has the same information about b like the
cast "cast(A)b": The memory area of b knows compatitibility to C
and also the alias.
For me, using alias this, the object b
V Thu, 11 Sep 2014 11:40:05 +
andre via Digitalmars-d-learn
napsáno:
> Hi,
>
> I am 80% sure, the failing assertion is correct but please have a
> look.
No it is not
assert(cast(A)cast(C)b); // this is OK
b is B so it does not know about having alias to A;
> Second assertion fails.
>
>
Hi,
I am 80% sure, the failing assertion is correct but please have a
look.
Second assertion fails.
Kind regards
André
class A{}
class B{}
class C : B
{
A a;
alias a this;
this()
{
a = new A();
}
}
void main()
{
B b =
Trying with
U opCast(U : Object)() {
return new U();
}
work fine. It isn't a solution, but i don't understand why this
works and the following not:
U opCast(U : Object)() {
return cast(U) this._obj;
}
I hope really some of you ca
