On Thu, Sep 23, 2010 at 12:39 AM, Camilo Uribe wrote:
> On Fri, Jul 9, 2010 at 12:03 AM, Johan De Meersman
> wrote:
> > This will mostly depend on your OS, really. Assuming you're running a
> 64-bit
> > flavour of *nix on that box, I don't think you have to worry.
>
> Linux on 64-bits.
>
Yes, bu
2010/9/23 Johnny Withers
>
> Can you show us the output of: show status like '%innodb%'
> JW
>
Sure.
mysql> show status like '%innodb%';
+---++
| Variable_name | Value |
+---+---
update mydata set column1 = column2, column2 = column1
(works in sqlserver, can't try mysql at the moment)
You can select which rows by adding a where clause obviously.
I suppose that the field values are copied to a buffer which is the written
to the table at the end of the update (or row by row
On Fri, Jul 9, 2010 at 12:03 AM, Johan De Meersman wrote:
> This will mostly depend on your OS, really. Assuming you're running a 64-bit
> flavour of *nix on that box, I don't think you have to worry.
Linux on 64-bits.
The default installation will use all the ram it needs or do I have to
config
Oh yea, INNER JOIN is cleaner to use
Rolando A. Edwards
MySQL DBA (CMDBA)
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New York, NY 10013
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-Original Message
This is even better!
JW
On Wed, Sep 22, 2010 at 2:27 PM, Steve Staples wrote:
> What about:
> select `id`, `column1` as 'column2', `column2` as 'column1';
>
> Steve
>
>
>
> On Wed, 2010-09-22 at 13:06 -0500, Johnny Withers wrote:
> > Couldn't you just rename the columns?
> >
> > JW
> >
> >
> >
Hi Rolando,
This is perfect solution I was looking for.
Why do you use left join here? It looks like inner join works fine as well.
Thanks.
Rolando Edwards wrote:
I ran these commands:
use test
DROP TABLE IF EXISTS mydata;
CREATE TABLE mydata (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,column1
Hi Rolando,
This is perfect solution I was looking for.
Why do you use left join here? It looks like inner join works fine as well.
Thanks.
>
>
>
>
>
> Rolando Edwards wrote:
>
> I ran these commands:
>
> use test
> DROP TABLE IF EXISTS mydata;
> CREATE TABLE mydata (id INT NOT NULL AUTO_INCREME
What about:
select `id`, `column1` as 'column2', `column2` as 'column1';
Steve
On Wed, 2010-09-22 at 13:06 -0500, Johnny Withers wrote:
> Couldn't you just rename the columns?
>
> JW
>
>
> On Wed, Sep 22, 2010 at 11:53 AM, Rolando Edwards
> wrote:
>
> > I ran these commands:
> >
> > use tes
Couldn't you just rename the columns?
JW
On Wed, Sep 22, 2010 at 11:53 AM, Rolando Edwards
wrote:
> I ran these commands:
>
> use test
> DROP TABLE IF EXISTS mydata;
> CREATE TABLE mydata (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,column1
> CHAR(1),column2 CHAR(2));
> INSERT INTO mydata (colum
I ran these commands:
use test
DROP TABLE IF EXISTS mydata;
CREATE TABLE mydata (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,column1
CHAR(1),column2 CHAR(2));
INSERT INTO mydata (column1,column2) VALUES ('a','z'), ('b','y'), ('c','x'),
('d','w'), ('e','v');
SELECT * FROM mydata;
UPDATE mydata A L
Can you show us the output of: show status like '%innodb%'
JW
On Tue, Sep 21, 2010 at 10:11 PM, vokern wrote:
> And this is the innodb file size, does this matter for performance?
>
> $ du -h ibdata*
> 11G ibdata1
> 11G ibdata2
> 11G ibdata3
> 59G ibdata4
>
>
>
> 2010/9/22 voke
Hi all.
Sorry for very simple question, just can't figure out the solution.
I need to swap data in column1 with data in column2.
++-+-+
| id | column1 | column2 |
++-+-+
| 1 | a | z |
| 2 | b | y |
| 3 | c | x |
| 4
Hi,
> If its an IO problem the first and easiest thing to do is (probably) look at
> your disk subsystem. You can easily achieve higher disk IO by increasing the
> number of disks and implementing something like RAID1+0.
Or you can be logical about it and try to determine whether the IO
performan
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